To calculate: The solution of the system of inequality and given he coordinates of any corner points.
The common region in the graph is the solution of the inequality.
Given Information:
The system of inequality is,
Calculation:
Consider the given system of inequality,
The boundary point is included if the inequality containing
In the first inequality, the boundary is
And,
The intercepts of the equation are
To determine the half-plane to be shaded, use a test point not on the boundary, say
The statement is true so the shade the half-plane where
In the second inequality, the boundary is
And,
The intercepts of the equation are
To determine the half-plane to be shaded, use a test point not on the boundary, say
The statement is true so the shade the half-plane where
In the third inequality, the boundary is
And,
The intercepts of the equation are
To determine the half-plane to be shaded, use a test point not on the boundary, say
The statement is not true so the shade the half-plane where
Now, make the graph of the inequality.
Thus, the shaded part by both the inequality is the solution of the inequality.
And the corner points are defined as,
Hence, the corner points are
Chapter 7 Solutions
PRECALCULUS:GRAPHICAL,...-NASTA ED.
- r>0 (r, 0) = T 0 and one with r 0 2 (c) (9,-17) 3 (r, 8) (r, 8) r> 0 r<0 (r, 0) = (r, 8) = X X X x x Warrow_forward74. Geometry of implicit differentiation Suppose x and y are related 0. Interpret the solution of this equa- by the equation F(x, y) = tion as the set of points (x, y) that lie on the intersection of the F(x, y) with the xy-plane (z = 0). surface Z = a. Make a sketch of a surface and its intersection with the xy-plane. Give a geometric interpretation of the result that dy dx = Fx F χ y b. Explain geometrically what happens at points where F = 0. yarrow_forwardExample 3.2. Solve the following boundary value problem by ADM (Adomian decomposition) method with the boundary conditions მი მი z- = 2x²+3 дг Əz w(x, 0) = x² - 3x, θω (x, 0) = i(2x+3). ayarrow_forward
- 6. A particle moves according to a law of motion s(t) = t3-12t2 + 36t, where t is measured in seconds and s is in feet. (a) What is the velocity at time t? (b) What is the velocity after 3 s? (c) When is the particle at rest? (d) When is the particle moving in the positive direction? (e) What is the acceleration at time t? (f) What is the acceleration after 3 s?arrow_forwardConstruct a table and find the indicated limit. √√x+2 If h(x) = then find lim h(x). X-8 X-8 Complete the table below. X 7.9 h(x) 7.99 7.999 8.001 8.01 8.1 (Type integers or decimals rounded to four decimal places as needed.)arrow_forwardUse the graph to find the following limits. (a) lim f(x) (b) lim f(x) X-1 x→1 (a) Find lim f(x) or state that it does not exist. Select the correct choice X-1 below and, if necessary, fill in the answer box within your choice. OA. lim f(x) = X-1 (Round to the nearest integer as needed.) OB. The limit does not exist. Qarrow_forward
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- Find all values x = a where the function is discontinuous. For each value of x, give the limit of the function as x approaches a. Be sure to note when the limit doesn't exist. f(x)=4x²+7x+1 Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice. (Use a comma to separate answers as needed.) OA. f is discontinuous at the single value x = B. f is discontinuous at the single value x = OC. f is discontinuous at the two values x = OD. fis discontinuous at the two values x = OE. f is discontinuous at the two values x = The limit is The limit does not exist and is not co or - oo. The limit for the smaller value is The limit for the larger value is The limit for both values do not exist and are not co or - co. The limit for the smaller value does not exist and is not oo or - co. The limit for the larger value isarrow_forwardFind all values x = a where the function is discontinuous. For each value of x, give the limit of the function as x approaches a. Be sure to note when the limit doesn't exist. 8+x f(x) = x(x-1) (Use a comma to separate answers as needed.) OA. The function f is discontinuous at the single value x = OB. The function f is discontinuous at the single value x = OC. The function f is discontinuous at the two values x = OD. The function f is discontinuous at the two values x = not oo or -0. OE. The function f is discontinuous at the two values x = The limit is The limit does not exist and is not oo or - co. The limits for both values do not exist and are not co or - co. The limit for the smaller value is The limit for the larger value does not exist and is The limit for the smaller value does not exist and is not co or - co. The limit for the largerarrow_forwardi need help please . and please dont use chat gpt i am trying to learn and see the mistake i did when solving minearrow_forward
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