The reason for the miscibility of ethanol in water and the immiscibility of cyclohexane in water has to be given. Concept introduction: ‘Like dissolves like’ principle said that polar compounds including ionic compound should be more soluble in polar solvent. Likewise, non-polar compound should be more soluble in non-polar solvent. Other hand, compounds with similar intermolecular force capability to soluble in one another because solute-solvent interactions are similar signification to the solute-solute interaction. ‘ The set of repulsive and attractive force between molecules that result from the polarity between neighboring molecules is represented as intermolecular force. There are four types of intermolecular forces: Hydrogen bonding London dispersion force Ion – dipole force Dipole – Dipole force Hydrogen bond: Hydrogen is bonded to strong electronegative atom like oxygen, nitrogen etc.

Question

Want to see the full answer?

Answer 1

Question

Chapter 7, Problem 50QRT

Interpretation Introduction

Interpretation:

The reason for the miscibility of ethanol in water and the immiscibility of cyclohexane in water has to be given.

Concept introduction:

‘Like dissolves like’ principle said that polar compounds including ionic compound should be more soluble in polar solvent. Likewise, non-polar compound should be more soluble in non-polar solvent. Other hand, compounds with similar intermolecular force capability to soluble in one another because solute-solvent interactions are similar signification to the solute-solute interaction.

‘The set of repulsive and attractive force between molecules that result from the polarity between neighboring molecules is represented as intermolecular force. There are four types of intermolecular forces:

Hydrogen bonding

London dispersion force

Ion – dipole force

Dipole – Dipole force

Hydrogen bond: Hydrogen is bonded to strong electronegative atom like oxygen, nitrogen etc.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Rank the labeled protons (Ha-Hd) in order of increasing acidity, starting with the least acidic. НОН НЬ OHd Онс

Can the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left? ? starting material target If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area. Be sure you follow the standard ALEKS rules for submitting syntheses. + More... Note for advanced students: you may assume that you are using a large excess of benzene as your starting material. C :0 T Add/Remove step G

The following equations represent the formation of compound MX. What is the AH for the electron affinity of X (g)? X₂ (g) → 2X (g) M (s) → M (g) M (g) M (g) + e- AH = 60 kJ/mol AH = 22 kJ/mol X (g) + e-X (g) M* (g) +X (g) → MX (s) AH = 118 kJ/mol AH = ? AH = -190 kJ/mol AH = -100 kJ/mol a) -80 kJ b) -30 kJ c) -20 kJ d) 20 kJ e) 156 kJ