Student Solutions Manual for Oxtoby/Gillis/Butler's Principles of Modern Chemistry, 8th
Student Solutions Manual for Oxtoby/Gillis/Butler's Principles of Modern Chemistry, 8th
8th Edition
ISBN: 9798214170251
Author: David W. Oxtoby, H. Pat Gillis and Laurie J. Butler
Publisher: Cengage Learning US
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Chapter 7, Problem 24P
Interpretation Introduction

Interpretation:

The reason should be determined for not forming an amide during the condensation of tertiary amine and carboxylic acid.

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon.

The compound containsat least one nitrogen atom (with one lone pair of electrons) which is linked with hydrogen atoms or alkyl or aryl groups are known as amine.It is a derivative of ammonia.

Amides: These are the derivatives of carboxylic acids in which the hydroxyl group is replaced by an ammonia or amine.

In carboxylic acid, carbonyl carbon is linked to carbon or hydrogen on one side and on other side linked to a heteroatom such as O, N, S. The general formula is RCOOH, where R is an alkyl group.

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need help please and thanks dont understand only need help with C-F Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).   Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%.   Part B - Compare difference in free energy to the thermal…
Please correct answer and don't used hand raiting
need help please and thanks dont understand a-b Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).   Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%.   Part B - Compare difference in free energy to the thermal energy Divide the…

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Student Solutions Manual for Oxtoby/Gillis/Butler's Principles of Modern Chemistry, 8th

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