Chapter 7, Problem 1P

To determine

The magnitude of the momentum of the sparrow.

Answer to Problem 1P

Momentum of the sparrow is 0.2352 kg-m/s.

Explanation of Solution

Given:

Mass of the sparrow is m = 28 gm = 0.028 kg and speed of the sparrow is v = 8.4 m/s.

Formula used:

Momentum is defined as mass times speed, that is , $p=mv$ .

Calculation:

Here $m=28$ gm = 0.028 kg and speed is $v=8.4$ m/s.

So,

  $\begin{array}{c}p=(0.028\times 8.4)\text{kg-m/s}\\ =0.2352\text{ kg-m/s}\end{array}$

Conclusion:

Therefore, the required momentum of the sparrow is 0.2352 kg-m/s.