
To Calculate: The average force on the ball during the contact.

Explanation of Solution
Given:
Mass of the baseball, m=0.145 kg
Initial horizontal velocity of ball, u=35.0 m/s ˆi
The height to which the ball reaches after contact with the bat, h=55.6 m
Contact time, Δt=1.4 ms
Formula Used:
Average force on the ball during the contact can be obtained using Newton’s second law of motion:
Favg=ΔpΔt=mΔvΔt
Here, Δp is the change in momentum, Δt is the contact time, Δv is the change in the velocity.
Also, velocity of the ball after the contact with the bat can be obtained using the formula:
v=√2gh
Here, g is the acceleration due to gravity and h is the height.
Calculations:
v=√2ghv=√2×9.8×55.6v=33 m/s ˆj
Average force:
Favg=ΔpΔt=mΔvΔt=m(v−u)Δt=0.145(33ˆj)−(−35ˆi)1.4×10−3s=3625 Nˆi+3418 NˆjFavg=√(3625 N)2+(3418 N)2=4982 Nθ=tan−134183625=43.3°
Conclusion:
Thus, the average force on the ball during contact is 4982 N at the angle 43.3° .
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