
The force of wind on person.
To compare: The maximum

Answer to Problem 9P
The force of wind acting on person is Fwind=833.4 N
The force acting on person due to wind greater than the force of friction.
Explanation of Solution
Given:
Mass of person, M=70 kg
Speed of wind, vwind=100 km/h
The rate of striking of air on person, R=40 kg/s
Formula used:
F=Δpt
Where, Δp = change in momentum
t = time interval
F = force
Calculation:
The wind strikes a person at a rate,
mwindt=(40)×(1.5)×(0.5)mwindt=30 kg/s
The speed of wind in m/s is,
vwind=(100)(518 ) m/s
The force experienced by the person due to motion of wind is,
Fwind=(mwindt)vwindFwind=(30 kg.s)(100×518 m.s)Fwind=(30)(27.78)Fwind=833.4 N (1)
The maximum friction force acting on the person is,
f=μsMgf=(1)(70)9.8f=686 N (2)
From, equation (1) and (2),
Fwind>f
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