Chemical Principles
8th Edition
ISBN: 9781337247269
Author: Steven S. Zumdahl; Donald J. DeCoste
Publisher: Cengage Learning US
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Chapter 7, Problem 138AE
One mole of a weak acid HA was dissolved in 2.0 L ofsolution. After the system had come to equilibrium, theconcentration of HA was found to be 0.45 M. Calculate
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Chapter 7 Solutions
Chemical Principles
Ch. 7 - Prob. 1DQCh. 7 - Differentiate between the terms strength and...Ch. 7 - Prob. 3DQCh. 7 - Prob. 4DQCh. 7 - Prob. 5DQCh. 7 - Prob. 6DQCh. 7 - Prob. 7DQCh. 7 - Prob. 8DQCh. 7 - Prob. 9DQCh. 7 - Prob. 10DQ
Ch. 7 - Prob. 11DQCh. 7 - Prob. 12DQCh. 7 - Prob. 13DQCh. 7 - Prob. 14DQCh. 7 - Prob. 15DQCh. 7 - Prob. 16DQCh. 7 - Prob. 17DQCh. 7 - Consider the autoionization of liquid ammonia:...Ch. 7 - The following are representations of acidbase...Ch. 7 - Prob. 20ECh. 7 - For each of the following aqueous reactions,...Ch. 7 - Write balanced equations that describe the...Ch. 7 - Write the dissociation reaction and the...Ch. 7 - Prob. 24ECh. 7 - Consider the following illustrations: Which beaker...Ch. 7 - Prob. 26ECh. 7 - Prob. 27ECh. 7 - Prob. 28ECh. 7 - Prob. 29ECh. 7 - Prob. 30ECh. 7 - Consider the reaction of acetic acid in water...Ch. 7 - Prob. 32ECh. 7 - Prob. 33ECh. 7 - Prob. 34ECh. 7 - Prob. 35ECh. 7 - Values of Kw as a function of temperature are as...Ch. 7 - Prob. 37ECh. 7 - Prob. 38ECh. 7 - Prob. 39ECh. 7 - Prob. 40ECh. 7 - Prob. 41ECh. 7 - Prob. 42ECh. 7 - Prob. 43ECh. 7 - A solution is prepared by adding 50.0 mL of 0.050...Ch. 7 - Prob. 45ECh. 7 - Prob. 46ECh. 7 - Prob. 47ECh. 7 - Prob. 48ECh. 7 - Calculate the concentration of all species present...Ch. 7 - Prob. 50ECh. 7 - Prob. 51ECh. 7 - Prob. 52ECh. 7 - Prob. 53ECh. 7 - Prob. 54ECh. 7 - A solution is prepared by dissolving 0.56 g of...Ch. 7 - At 25°C a saturated solution of benzoic acid (see...Ch. 7 - Prob. 57ECh. 7 - Prob. 58ECh. 7 - A solution contains a mixture of acids: 0.50 M HA...Ch. 7 - Prob. 60ECh. 7 - Prob. 61ECh. 7 - Prob. 62ECh. 7 - Prob. 63ECh. 7 - Prob. 64ECh. 7 - Prob. 65ECh. 7 - Trichloroacetic acid (CCl3CO2H) is a corrosive...Ch. 7 - Prob. 67ECh. 7 - Prob. 68ECh. 7 - Prob. 69ECh. 7 - Prob. 70ECh. 7 - Prob. 71ECh. 7 - Prob. 72ECh. 7 - Prob. 73ECh. 7 - Prob. 74ECh. 7 - Prob. 75ECh. 7 - Prob. 76ECh. 7 - Prob. 77ECh. 7 - Prob. 78ECh. 7 - Prob. 79ECh. 7 - Prob. 80ECh. 7 - Calculate the pH of a 0.20 M C2H5NH2 solution...Ch. 7 - Prob. 82ECh. 7 - Prob. 83ECh. 7 - Prob. 84ECh. 7 - Prob. 85ECh. 7 - Quinine (C20H24N2O2) is the most important...Ch. 7 - Prob. 87ECh. 7 - Prob. 88ECh. 7 - Prob. 89ECh. 7 - Prob. 90ECh. 7 - Prob. 91ECh. 7 - Prob. 92ECh. 7 - Prob. 93ECh. 7 - Prob. 94ECh. 7 - A typical vitamin C tablet (containing pure...Ch. 7 - Prob. 96ECh. 7 - Prob. 97ECh. 7 - Prob. 98ECh. 7 - Prob. 99ECh. 7 - Prob. 100ECh. 7 - Rank the following 0.10 M solutions in order of...Ch. 7 - Prob. 102ECh. 7 - Prob. 103ECh. 7 - Prob. 104ECh. 7 - Prob. 105ECh. 7 - Prob. 106ECh. 7 - Prob. 107ECh. 7 - Prob. 108ECh. 7 - Prob. 109ECh. 7 - Prob. 110ECh. 7 - Prob. 111ECh. 7 - Prob. 112ECh. 7 - Prob. 113ECh. 7 - Prob. 114ECh. 7 - Prob. 115ECh. 7 - Prob. 116ECh. 7 - Prob. 117ECh. 7 - Prob. 118ECh. 7 - Prob. 119ECh. 7 - Prob. 120ECh. 7 - Prob. 121ECh. 7 - Prob. 122ECh. 7 - Calculate the pH of a 7.0107M HCl solution.Ch. 7 - Calculate the pH of a 1.0107M solution of NaOHin...Ch. 7 - Prob. 125AECh. 7 - Prob. 126AECh. 7 - Prob. 127AECh. 7 - Prob. 128AECh. 7 - Hemoglobin (abbreviated Hb) is a protein that is...Ch. 7 - Prob. 130AECh. 7 - Prob. 131AECh. 7 - Prob. 132AECh. 7 - Prob. 133AECh. 7 - Prob. 134AECh. 7 - Prob. 135AECh. 7 - Prob. 136AECh. 7 - Prob. 137AECh. 7 - One mole of a weak acid HA was dissolved in 2.0 L...Ch. 7 - Prob. 139AECh. 7 - Prob. 140AECh. 7 - Prob. 141AECh. 7 - Will 0.10 M solutions of the following salts be...Ch. 7 - Prob. 143AECh. 7 - Prob. 144AECh. 7 - Prob. 145AECh. 7 - Prob. 146AECh. 7 - Prob. 147AECh. 7 - Prob. 148AECh. 7 - Prob. 149AECh. 7 - Prob. 150AECh. 7 - Prob. 151AECh. 7 - Prob. 152CPCh. 7 - Prob. 153CPCh. 7 - A typical solution of baking soda (sodium...Ch. 7 - Prob. 155CPCh. 7 - Prob. 156CPCh. 7 - Prob. 157CPCh. 7 - Prob. 158CPCh. 7 - Prob. 159CPCh. 7 - Prob. 160CPCh. 7 - Prob. 161CPCh. 7 - Prob. 162CPCh. 7 - Prob. 163CPCh. 7 - Prob. 164CPCh. 7 - Prob. 165CPCh. 7 - Prob. 166CPCh. 7 - Prob. 167CPCh. 7 - Prob. 168CPCh. 7 - Prob. 169MP
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- The equilibrium equations and Ka values for three reaction systems are given below. H2C2O4(aq)+H2OH3O+(aq)+HC2O4(aq);Ka=5.6102H3PO4(aq)+H2OH3O+(aq)+H2PO4(aq);Ka=6.9103HCOOH(aq)+H2OH3O+(aq)+HCOO(aq);Ka=1.7104 a Which conjugate pair would be best for preparing a buffer with a pH of 2.88? b How would you prepare 50 mL of a buffer with a pH of 2.88 assuming that you had available 0.10 M solutions of each pair?arrow_forwardMalic acid is a weak diprotic organic acid with Ka1 = 4.0 104 and Ka2 = 9.0 105. a Letting the symbol H2A represent malic acid, write the chemical equations that represent Ka1 and Ka2. Write the chemical equation that represents Ka1 Ka2. b Qualitatively describe the relative concentrations of H2A, HA, A2, and H3O+ in a solution that is about one molar in malic acid. c Calculate the pH of a 0.0175 M malic acid solution and the equilibrium concentration of [H2A]. d What is the A2 concentrationin in solutions b and c?arrow_forwardMethylammonium chloride is a salt of methylamine, CH3NH2. A 0.10 M solution of this salt has a pH of 5.82. a Calculate the value for the equilibrium constant for the reaction CH3NH3++H2OCH3NH2+H3O+ b What is the Kb value for methylamine? c What is the pH of a solution in which 0.450 mol of solid methylammonium chloride is added to 1.00 L of a 0.250 M solution of methylamine? Assume no volume change.arrow_forward
- Sodium benzoate is a salt of benzoic acid, C6H5COOH. A 0.15 M solution of this salt has a pOH of 5.31 at room temperature. a Calculate the value for the equilibrium constant for the reaction C6H5COO+H2OC6H5COOH+OH b What is the Ka value for benzoic acid? c Benzoic acid has a low solubility in water. What is its molar solubility if a saturated solution has a pH of 2.83 at room temperature?arrow_forwardTartaric acid is a weak diprotic fruit acid with Ka1 = 1.0 103 and Ka2 = 4.6 105. a Letting the symbol H2A represent tartaric acid, write the chemical equations that represent Ka1 and Ka2. Write the chemical equation that represents Ka1 Ka2. b Qualitatively describe the relative concentrations of H2A, HA, A2, and H3O+ in a solution that is about 0.5 M in tartaric acid. c Calculate the pH of a 0 0250 M tartaric acid solution and the equilibrium concentration of [H2A]. d What is the A2 concentration in solutions b and c?arrow_forwardFor conjugate acidbase pairs, how are Ka and Kb related? Consider the reaction of acetic acid in water CH3CO2H(aq)+H2O(l)CH3CO2(aq)+H3O+(aq) where Ka = 1.8 105 a. Which two bases are competing for the proton? b. Which is the stronger base? c. In light of your answer to part b. why do we classify the acetate ion (CH3CO2) as a weak base? Use an appropriate reaction to justify your answer. In general, as base strength increases, conjugate acid strength decreases. Explain why the conjugate acid of the weak base NH3 is a weak acid. To summarize, the conjugate base of a weak acid is a weak base and the conjugate acid of a weak base is a weak acid (weak gives you weak). Assuming Ka for a monoprotic strong acid is 1 106, calculate Kb for the conjugate base of this strong acid. Why do conjugate bases of strong acids have no basic properties in water? List the conjugate bases of the six common strong acids. To tie it all together, some instructors have students think of Li+, K+, Rb+, Cs+, Ca2+, Sr2+, and Ba2+ as the conjugate acids of the strong bases LiOH, KOH. RbOH, CsOH, Ca(OH)2, Sr(OH)2, and Ba(OH)2. Although not technically correct, the conjugate acid strength of these cations is similar to the conjugate base strength of the strong acids. That is, these cations have no acidic properties in water; similarly, the conjugate bases of strong acids have no basic properties (strong gives you worthless). Fill in the blanks with the correct response. The conjugate base of a weak acid is a_____base. The conjugate acid of a weak base is a_____acid. The conjugate base of a strong acid is a_____base. The conjugate acid of a strong base is a_____ acid. (Hint: Weak gives you weak and strong gives you worthless.)arrow_forward
- Weak base B has a pKb of 6.78 and weak acid HA has a pKa of 5.12. a Which is the stronger base, B or A? b Which is the stronger acid, HA or BH+? c Consider the following reaction: B(aq)+HA(aq)BH+(aq)+A(aq) Based on the information about the acid/base strengths for the species in this reaction, is this reaction favored to proceed more to the right or more to the left? Why? d An aqueous solution is made in which the concentration of weak base B is one half the concentration of its acidic salt, BHCl, where BH+ is the conjugate weak add of B. Calculate the pH of the solution. e An aqueous solution is made in which the concentration of weak acid HA twice the concentration of the sodium salt of the weak acid, NaA. Calculate the pH of the solution. f Assume the conjugate pairs B/BH+ and HA/A are capable of being used as color-based end point indicators in acidbase titrations, where B is the base form indicator and BH is the acid form indicator, and HA is the acid form indicator and A is the base form indicator. Select the indicator pair that would be best to use in each of the following titrations: (1) Titration of a strong acid with a strong base. (i) B/BH+ (ii) HA/A (2) Titration of a weak base with a strong acid. (i) B/BH+ (ii) HA/Aarrow_forwardA friend asks the following: Consider a buffered solution made up of the weak acid HA and its salt NaA. If a strong base like NaOH is added, the HA reacts with the OH to form A. Thus the amount of acid (HA) is decreased, and the amount of base (A) is increased. Analogously, adding HCI to the buffered solution forms more of the acid (HA) by reacting with the base (A). Thus how can we claim that a buffered solution resists changes in the pH of the solution? How would you explain buffering to this friend?arrow_forwardKa for formic acid is 1.7 104 at 25C. A buffer is made by mixing 529 mL of 0.465 M formic acid, HCHO2, and 494 mL of 0.524 M sodium formate, NaCHO2. Calculate the pH of this solution at 25C after 110 mL of 0.152 M HCl has been added to this buffer.arrow_forward
- Find the values of Kb for the conjugate bases of the following organic acids: (a) glycolic acid, used by dermatologists as a chemical peel; K a =1.5104 (b) butyric acid, responsible for the odor of rancid butter; K a =1.5105arrow_forwardA chemist wanted to determine the concentration of a solution of lactic acid, HC3H5O3. She found that the pH of the solution was 2.60. What was the concentration of the solution? The Kd of lactic acid is 1.4 104.arrow_forwardA 0.239-g sample of unknown organic base is dissolved in water and titrated with a 0.135 M hydrochloric acid solution. After the addition of 18.35 mL of acid, a pH of 10.73 is recorded. The equivalence point is reached when a total of 39.24 mL of HCl is added. The base and acid combine in a 1:1 ratio. a What is the molar mass of the organic base? b What is the Kb value for the base? The Kb value could have been determined very easily if a pH measurement had been made after the addition of 19.62 mL of HCl. Why?arrow_forward
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