Chapter 6.4, Problem 48CCR

To determine

To find: Sum.

Answer to Problem 48CCR

  $\frac{-1}{6}+\frac{7}{18}=\frac{2}{9}$

Explanation of Solution

Given information:

  $-\frac{1}{6}+\frac{7}{18}$

  $\begin{array}{l}-\frac{1}{6}+\frac{7}{18}\\ =\left(-\frac{1}{6}\times \frac{3}{3}\right)+\frac{7}{18}\\ =\left(-\frac{1\times 3}{6\times 3}\right)+\frac{7}{18}\\ =\frac{-3}{18}+\frac{7}{18}\\ =\frac{-3+7}{18}\\ =\frac{4}{18}\\ =\frac{2}{9}\end{array}$

Therefore

  $\frac{-1}{6}+\frac{7}{18}=\frac{2}{9}$