Chapter 6.3, Problem 24IP

a.

To determine

Calculate the percent of Bartoli’s receiving points won.

Answer to Problem 24IP

The percentage of receiving points won is $32\%$ .

Explanation of Solution

Given:

It is given in the question that the receiving points won by Bartoli is $16$ out of $50$ .

Concept Used:

In this, use the concept of percent equation and the equation is $Part=Percent\cdot Whole$ .

Calculation:

In this, the part and the whole are given, looking for a part. Let p represent percent.

  $\begin{array}{l}Part=Percent\cdot Whole\\ 16=p\cdot 50\\ p=\frac{16}{50}\\ p=0.32\\ p=0.32\cdot 100\\ p=32\%\end{array}$

Conclusion:

The percentage is $32\%$ .

b.

To determine

Answer to Problem 24IP

Williams has a greater percent with $70\%$ .

Explanation of Solution

Given: It is given in the question that the first serves for bartoli and williams are $40of63$ and $35of50$ .

Concept Used:

In this, use the concept of percent equation and the equation is $Part=Percent\cdot Whole$ .

Calculation:

For Bartoli:

In this, the part and the whole are given, looking for a part. Let p represent percent.

  $\begin{array}{l}Part=Percent\cdot Whole\\ 40=p\cdot 63\\ p=\frac{40}{63}\\ p=0.635\\ p=0.635\cdot 100\\ p=63.5\%\end{array}$

For Williams:

In this, the part and the whole are given, looking for a part. Let p represent percent.

  $\begin{array}{l}Part=Percent\cdot Whole\\ 35=p\cdot 50\\ p=\frac{35}{50}\\ p=0.7\\ p=0.7\cdot 100\\ p=70\%\end{array}$

Conclusion:

Williams has a greater percent.

c.

To determine

Find the number of times it convert on break point opportunities.

Answer to Problem 24IP

The number of times that break point opportunities will be $6$ .

Explanation of Solution

Given: It is given in the question that Williams has a $4of10$ break point conversion.

Concept Used:

In this, use the concept of percent equation and the equation is $Part=Percent\cdot Whole$ .

Calculation:

In this, the part and the whole are given, looking for a part. Let p represent percent.

  $\begin{array}{l}Part=Percent\cdot Whole\\ 4=p\cdot 10\\ p=\frac{4}{10}\\ p=0.4\\ p=0.4\cdot 100\\ p=40\%\end{array}$

Her predicted conversions would be $40\%of16$ , or

  $\begin{array}{l}40\%of16\\ \frac{40}{100}\times 16\\ 0.4\times 16\\ 6.4\approx 6\end{array}$

Conclusion:

The number of times will be $6$ .