Chapter 6.4, Problem 22IP

To determine

To find: Percent error.

Answer to Problem 22IP

Percent error is $3.33\%$

Explanation of Solution

Given information:

Actual number of vitamins present = Original value $=62$

A bottle of vitamins should have vitamins = Actual number $=60$ .

Percent error $=\frac{A}{O}\times 100$

Where

  $A=$ Absolute value.

  $O=$ Actual value.

From given information

Actual number of vitamins present = Original value $=62$

A bottle of vitamins should have vitamins = Actual value $=60$ .

Absolute value = Original value $-$ Actual value.

  $\begin{array}{l}\Rightarrow A=62-60\\ \Rightarrow A=2\end{array}$

Therefore,

Percent error $=\frac{2}{60}\times 100$

  $\Rightarrow$ Percent error $=\frac{200}{60}$

  $\Rightarrow$ Percent error $=3.3333$

To nearest hundredth, Percent error is $3.33\%$ .