Chapter 6.4, Problem 26IP

To determine

To find: Percent error.

Answer to Problem 26IP

Percent error is $-7.8\%$

Explanation of Solution

Given information:

Volume of replaced container = Estimated value $=59$ ounces

Actual volume of container = Actual value $=$ half gallon.

Percent error $=\frac{A}{O}\times 100$

Where

  $A=$ Absolute value.

  $O=$ Actual value.

From given information

Volume of replaced container = Estimated value $=59$ ounces

Actual volume of container = Actual value $=$ half gallon.

We know

  $1$ gallon $=128$ ounces.

Therefore,

Half gallon = $=64$ ounces.

Actual volume of container = Actual value $=64$ ounces

Absolute value = Estimated value $-$ Actual value.

  $\begin{array}{l}\Rightarrow A=59-64\\ \Rightarrow A=-5\end{array}$

Therefore,

Percent error $=\frac{-5}{64}\times 100$

  $\Rightarrow$ Percent error $=\frac{-500}{64}$

  $\Rightarrow$ Percent error $=-7.8125$

To nearest tenth, Percent error is $-7.8\%$ .