
a.
To choose a combination of 9 objects and find the score
a.

Answer to Problem 33PPS
11 points
Explanation of Solution
Given:
Each paper clip is worth 1 point
Each penny is worth 3 points
Calculation:
Let p represent the number of pennies and c represent the number of paper clips.
Let us choose 2 pennies and 5 paperclips
Then to calculate the score,
Conclusion:
Therefore, the score of our choice of combination is 11 points.
b.
To write and solve the system of equations to find the number of pennies and paper clips
b.

Answer to Problem 33PPS
Explanation of Solution
Given:
Number of pennies and paper clips is 15 points
Total of 9 objects are used.
Calculation:
Let p represent the number of pennies and c represent the number of paper clips.
Total number of coins used is 9.
The value of coins and paper clips is 15.
Subtract equation (1) from equation (2).
Substitute the value of p in equation (1).
Conclusion:
Therefore, the number of pennies is 3 and the number of paper clips is 6.
c.
To construct a table showing the number of paper clips and total points when the number of pennies is as given.
c.

Explanation of Solution
Given:
The number of pennies is 0, 1, 2, 3, 4 or 5.
Calculation:
Construct the table as follows.
Pennies ( p ) | 0 | 1 | 2 | 3 | 4 | 5 |
Paper clips (9 - p ) | 9 | 8 | 7 | 6 | 5 | 4 |
Points | 9 | 11 | 13 | 15 | 17 | 19 |
Conclusion:
The above table shows the total points for the mentioned pennies.
d.
To check if the table matches the result in subpart (b)
d.

Answer to Problem 33PPS
Yes
Explanation of Solution
Since the pennies are 3 points each, 3 of them make 9 points.
Add the 6 points from 6 paper clips and 15 points is obtained.
Using 9 objects, there is no other way of obtaining a score of 15 points.
Chapter 6 Solutions
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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