
a.
To choose a combination of 9 objects and find the score
a.

Answer to Problem 33PPS
11 points
Explanation of Solution
Given:
Each paper clip is worth 1 point
Each penny is worth 3 points
Calculation:
Let p represent the number of pennies and c represent the number of paper clips.
Let us choose 2 pennies and 5 paperclips
Then to calculate the score,
Conclusion:
Therefore, the score of our choice of combination is 11 points.
b.
To write and solve the system of equations to find the number of pennies and paper clips
b.

Answer to Problem 33PPS
Explanation of Solution
Given:
Number of pennies and paper clips is 15 points
Total of 9 objects are used.
Calculation:
Let p represent the number of pennies and c represent the number of paper clips.
Total number of coins used is 9.
The value of coins and paper clips is 15.
Subtract equation (1) from equation (2).
Substitute the value of p in equation (1).
Conclusion:
Therefore, the number of pennies is 3 and the number of paper clips is 6.
c.
To construct a table showing the number of paper clips and total points when the number of pennies is as given.
c.

Explanation of Solution
Given:
The number of pennies is 0, 1, 2, 3, 4 or 5.
Calculation:
Construct the table as follows.
Pennies ( p ) | 0 | 1 | 2 | 3 | 4 | 5 |
Paper clips (9 - p ) | 9 | 8 | 7 | 6 | 5 | 4 |
Points | 9 | 11 | 13 | 15 | 17 | 19 |
Conclusion:
The above table shows the total points for the mentioned pennies.
d.
To check if the table matches the result in subpart (b)
d.

Answer to Problem 33PPS
Yes
Explanation of Solution
Since the pennies are 3 points each, 3 of them make 9 points.
Add the 6 points from 6 paper clips and 15 points is obtained.
Using 9 objects, there is no other way of obtaining a score of 15 points.
Chapter 6 Solutions
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
Additional Math Textbook Solutions
University Calculus: Early Transcendentals (4th Edition)
Elementary Statistics (13th Edition)
Algebra and Trigonometry (6th Edition)
Calculus: Early Transcendentals (2nd Edition)
A First Course in Probability (10th Edition)
- 2) If Mand N be two water hyper Plane ofx Show that MUN and MN is hy Per Plane ofx with prove and Examplame. or 3) IS AUB is convex set and affine set or blensed set or symmetre setorsubsie.... Show that A and B is convex or affine or Hensedsed or symmetivce or subspace. 4) 18 MUN is independence show that Prove or ExPlane Mand Nave independend. or not. 5) Jet X be Vector Pace over I show that is xty tnx st Xty 3 fix→ F s-t f(x) (9) Jet Mand N be two blanced set of Xbe Vector space show tha MUNIS ansed setarrow_forwardFind a polynomial with integer coefficients that satisfies the given conditions. T(x) has degree 4, zeros i and 1 + i, and constant term 12.arrow_forwardHow to solve 2542000/64132 without a calculator?arrow_forward
- How much is the circumference of a circle whose diameter is 7 feet?C =π darrow_forwardHow to solve 2542/64.132arrow_forwardAssume that you fancy polynomial splines, while you actually need ƒ(t) = e²/3 – 1 for t€ [−1, 1]. See the figure for a plot of f(t). Your goal is to approximate f(t) with an inter- polating polynomial spline of degree d that is given as sa(t) = • Σk=0 Pd,k bd,k(t) so that sd(tk) = = Pd,k for tk = −1 + 2 (given d > 0) with basis functions bd,k(t) = Σi±0 Cd,k,i = • The special case of d 0 is trivial: the only basis function b0,0 (t) is constant 1 and so(t) is thus constant po,0 for all t = [−1, 1]. ...9 The d+1 basis functions bd,k (t) form a ba- sis Bd {ba,o(t), ba,1(t), bd,d(t)} of the function space of all possible sα (t) functions. Clearly, you wish to find out, which of them given a particular maximal degree d is the best-possible approximation of f(t) in the least- squares sense. _ 1 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0 -0.1 -0.2 -0.3 -0.4 -0.5 -0.6 -0.7 -0.8 -0.9 -1 function f(t) = exp((2t)/3) - 1 to project -1 -0.9 -0.8 -0.7 -0.6 -0.5 -0.4 -0.3 -0.2 -0.1 0 0.1 0.2 0.3 0.4 0.5…arrow_forward
- An image processor considered a 750×750 pixels large subset of an image and converted it into gray-scale, resulting in matrix gIn - a false-color visualization of gIn is shown in the top-left below. He prepared a two-dim. box filter f1 as a 25×25 matrix with only the 5×5 values in the middle being non-zero – this filter is shown in the top-middle position below. He then convolved £1 with itself to get £2, before convolving £2 with itself to get f3. In both of the steps, he maintained the 25×25 size. Next, he convolved gIn with £3 to get gl. Which of the six panels below shows g1? Argue by explaining all the steps, so far: What did the image processor do when preparing ₤3? What image processing operation (from gin to g1) did he prepare and what's the effect that can be seen? Next, he convolved the rows of f3 with filter 1/2 (-1, 8, 0, -8, 1) to get f4 - you find a visualization of filter f 4 below. He then convolved gIn with f4 to get g2 and you can find the result shown below. What…arrow_forward3ur Colors are enchanting and elusive. A multitude of color systems has been proposed over a three-digits number of years - maybe more than the number of purposes that they serve... - Everyone knows the additive RGB color system – we usually serve light-emitting IT components like monitors with colors in that system. Here, we use c = (r, g, b) RGB with r, g, bЄ [0,1] to describe a color c. = T For printing, however, we usually use the subtractive CMY color system. The same color c becomes c = (c, m, y) CMY (1-c, 1-m, 1-y) RGB Note how we use subscripts to indicate with coordinate system the coordinates correspond to. Explain, why it is not possible to find a linear transformation between RGB and CMY coordinates. Farbenlehr c von Goethe Erster Band. Roſt einen Defte mit fergen up Tübingen, is et 3. Cotta'fden Babarblung. ISIO Homogeneous coordinates give us a work-around: If we specify colors in 4D, instead, with the 4th coordinate being the homogeneous coordinate h so that every actual…arrow_forwardCan someone provide an answer & detailed explanation please? Thank you kindly!arrow_forward
- Algebra and Trigonometry (6th Edition)AlgebraISBN:9780134463216Author:Robert F. BlitzerPublisher:PEARSONContemporary Abstract AlgebraAlgebraISBN:9781305657960Author:Joseph GallianPublisher:Cengage LearningLinear Algebra: A Modern IntroductionAlgebraISBN:9781285463247Author:David PoolePublisher:Cengage Learning
- Algebra And Trigonometry (11th Edition)AlgebraISBN:9780135163078Author:Michael SullivanPublisher:PEARSONIntroduction to Linear Algebra, Fifth EditionAlgebraISBN:9780980232776Author:Gilbert StrangPublisher:Wellesley-Cambridge PressCollege Algebra (Collegiate Math)AlgebraISBN:9780077836344Author:Julie Miller, Donna GerkenPublisher:McGraw-Hill Education





