Chapter 6.2, Problem 18PPS

To determine

To find: Values of x and y.

Answer to Problem 18PPS

  $\begin{array}{l}x=0\\ y=1\end{array}$

Explanation of Solution

Given information:

  $\begin{array}{l}y=-3x+1\\ 2x+y=1\end{array}$

  $y=-3x+1$ -----(1)

  $2x+y=1$ ------(2)

Substitute the value of y from equation-(1) in equation-(2)

We get

  $\begin{array}{l}y=-3x+1\\ 2x+y=1\\ \Rightarrow 2x-3x+1=1\\ \Rightarrow -x+1=1\\ \Rightarrow x=1-1\\ \Rightarrow x=0\end{array}$

Substitute value of $x$ in equation-(1)

We get

  $\begin{array}{l}y=-3x+1\\ \Rightarrow y=-3\left(0\right)+1\\ \Rightarrow y=-0+1\\ \Rightarrow y=1\end{array}$

Therefore, values of x and y are

  $\begin{array}{l}x=0\\ y=1\end{array}$