Chapter 6.3, Problem 2CYU

To determine

To solve the given system of equations using elimination method

Answer to Problem 2CYU

$x=1$ and $y=6$

Explanation of Solution

Given:

Equations:

$8x+5y=38$

$-8x+2y=4$

Calculation:

Let,

$\begin{array}{l}8x+5y=\mathrm{38.......}(i)\\ -8x+2y=\mathrm{4.......}(ii)\end{array}$

Now, add equation ( i ) and equation ( ii ),

$\begin{array}{l}\Rightarrow (8x+5y)+(-8x+2y)=38+4\\ \Rightarrow 8x+5y-8x+2y=42\\ \Rightarrow 7y=42\\ \Rightarrow y=6\end{array}$

Now, substitute the value of x in equation ( i ),

$\begin{array}{l}\Rightarrow 8x+5\times 6=38\\ \Rightarrow 8x+30=38\\ \Rightarrow x=1\end{array}$

Conclusion:

Therefore, the required solution for the given system of equation is $x=1$ and $y=6$ .