Chapter 6.2, Problem 7CYU

a.

To determine

To find: Variables and equations.

Answer to Problem 7CYU

variables are $X$ and $Y$ .

  $X+Y={180}^0$

  $X={24}^0+Y$

  $\begin{array}{l}X={102}^0\\ Y={78}^0\end{array}$

Explanation of Solution

Given information:

  $\begin{array}{l}X+Y={180}^0\\ X={24}^0+Y\end{array}$

Here variables are $X$ and $Y$ .

  $X+Y={180}^0$ -----(1)

  $X={24}^0+Y$ -----(2)

b.

To determine

To find: Values of X and Y..

Answer to Problem 7CYU

  $\begin{array}{l}X={102}^0\\ Y={78}^0\end{array}$

Explanation of Solution

Given information:

  $\begin{array}{l}X+Y={180}^0\\ X={24}^0+Y\end{array}$

Here variables are $X$ and $Y$ .

  $X+Y={180}^0$ -----(1)

  $X={24}^0+Y$ -----(2)

Substitute the value of $X$ from equation-(2) in equation-(1)

We get

  $\begin{array}{l}\Rightarrow {24}^0+Y+Y={180}^0\\ \Rightarrow 2Y={180}^0-{24}^0\\ \Rightarrow 2Y={156}^0\\ \Rightarrow Y=\frac{{156}^0}{2^0}\\ \Rightarrow Y={78}^0\end{array}$

Substitute value of $Y$ in equation-(1)

We get

  $\begin{array}{l}X+Y={180}^0\\ \Rightarrow X+{78}^0={180}^0\\ \Rightarrow X={180}^0-{78}^0\\ \Rightarrow X={102}^0\end{array}$

Therefore, values of X and Y are

  $\begin{array}{l}X={102}^0\\ Y={78}^0\end{array}$