Chapter 6.2, Problem 4CYU

To determine

To find: Values of x and y.

Answer to Problem 4CYU

No solution.

Explanation of Solution

Given information:

  $\begin{array}{l}2x+3y=4\\ 4x+6y=9\end{array}$

  $2x+3y=4$

  $\Rightarrow 2x=4-3y$

$\begin{array}{l}\Rightarrow x=\frac{4-3y}{2}\\ \end{array}$ -----(1)

$4x+6y=9$ ------(2)

Substitute the value of $x$ from equation-(1) in equation-(2)

We get

  $\begin{array}{l}4x+6y=9\\ \Rightarrow 4\left(\frac{4-3y}{2}\right)+6y=9\\ \Rightarrow 2\left(4-3y\right)+6y=9\\ \Rightarrow 2\left(4\right)-2\left(3y\right)+6y=9\\ \Rightarrow 8-6y+6y=9\\ \Rightarrow 8=9\end{array}$

Which is not true

So there will be no solution.

As both the given equations are parallel lines they do not intersect each other.

Therefore, values of x and y are no solution.