Chapter 6.2, Problem 1PPB

Interpretation Introduction

Interpretation:

The region of electromagnetic spectra of a photon is to be determined that have twice as much energy as in the blue region of wavelength $442\text{ nm}$.

Concept introduction:

Electromagnetic wave has an electric field component and a magnetic field component having same wavelength and frequency.

The range of wavelengths of electromagnetic radiations and their respective frequencies are comprised in the electromagnetic spectrum.

The energy of a photon can be expressed as follows:

$\text{E}=\frac{\text{hc}}{\text{λ}}$

Here, E is the energy of the photon, $\text{h}$ is Planck’s constant $\left(6.63\times {10}^{-34}\text{ J}\cdot \text{s}\right)$, $\text{c}$ is the speed of light $\left(3.0\times {10}^8\text{ m/s}\right)$, and $\text{λ}$ is the wavelength.