Chapter 6, Problem 132AP

Interpretation Introduction

Interpretation:

The number of photons corresponding to light of 575 nm wavelength is to be determined.

Concept introduction:

Frequency is the number of wave passing through a point per second. It is represented by $\nu$.

The energy of a photon can be expressed as:

$\begin{array}{c}\text{E}=\text{h}\nu \\ \text{or, E}=\frac{\text{hc}}{\lambda }\end{array}$

Here, E is the energy of photon, $\text{h}$ is Planck’s constant $\left(6.63\times {10}^{-34}\text{ J}\cdot \text{s}\right)$, $\text{c}$ is the speed of light $\left(3.0\times {10}^8\text{ m/s}\right)$, $\lambda$ is the wavelength, and $\nu$ is frequency.

Convert nanometer to meter, since, $\text{1 nanometer}=\text{1}{0}^{-\text{9}}\text{ meter}$,

Conversion factor is $\left(\frac{1\text{ nm}}{1\times {10}^{-9}\text{ m}}\right)$.