Chapter 6, Problem 120AP

Interpretation Introduction

Interpretation:

The velocity of an ejected electron when a light of wavelength of $313\text{ nm}$

is allowed to shine onto the metal is to be determined.

Concept introduction:

The energy of a photon can be expressed as follows:

$\text{E}=\frac{\text{hc}}{\lambda }$

Here, $\text{E}$ denotes the energy of the photon, $\text{h}$ denotes Planck’s constant $\left(6.63\times {10}^{-34}\text{ J}\cdot \text{s}\right)$, $\text{c}$ denotes the speed of light $\left(3.0\times {10}^8\text{ m/s}\right)$, and $\lambda$ denotes the wavelength.

The relationship between wavelength and frequency is as follows:

$\text{c}=\lambda \times \nu$

Here, $\text{c}$ is the speed of light $\left(3.0\times {10}^8\text{ m/s}\right)$, $\lambda$ is the wavelength, and $\nu$

is the frequency

Conversion for meter to nanometer is $\frac{1\text{ nm}}{1\times {10}^{-9}\text{ m}}$.