![Introductory Chemistry: A Foundation](https://www.bartleby.com/isbn_cover_images/9781337399425/9781337399425_largeCoverImage.gif)
Concept explainers
(a)
Interpretation:
To balance the given chemical equation.
Concept Introduction:
Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the
(a)
![Check Mark](/static/check-mark.png)
Answer to Problem 75AP
Explanation of Solution
The unbalanced equation has 4 chlorine on the reactant side and two chlorine on the product side. To balance it, 2 is multiplied on the magnesium on both the sides.
The balanced equation is given as,
(b)
Interpretation:
To balance the given chemical equation.
Concept Introduction:
Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.
![Check Mark](/static/check-mark.png)
Answer to Problem 75AP
The balanced equation is
Explanation of Solution
The given equation is,
The unbalanced equation has 2 chlorine on the reactant side and 1 chlorine on the product side. To balance it, 2 is multiplied on the nitrogen oxide on reactant side and 2 is multiplied on the nitrosyl chloride on the product side.
The balanced equation is
(c)
Interpretation:
To balance the given chemical equation.
Concept Introduction:
Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.
![Check Mark](/static/check-mark.png)
Answer to Problem 75AP
Explanation of Solution
The given equation is,
The unbalanced equation has 2oxygen on the reactant side and 3 oxygen on the product side. To balance it, 3 is multiplied on the manganese dioxide and 4 on the aluminum on the reactant and on product side 3 is multiplied on the manganese and 2 on the aluminum oxide on the product side.
The balanced equation is,
(d)
Interpretation:
To balance the given chemical equation.
Concept Introduction:
Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.
![Check Mark](/static/check-mark.png)
Answer to Problem 75AP
Explanation of Solution
The given equation is,
The unbalanced equation has 8sulphur on the reactant side and 3 sulphur on the product side. To balance it, 16is multiplied on the chromium and 3 on the octasulphur on reactant side and 8 is multiplied on the Chromium sulfide on the product side.
The balanced equation is,
(e)
Interpretation:
To balance the given chemical equation.
Concept Introduction:
Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.
![Check Mark](/static/check-mark.png)
Answer to Problem 75AP
Explanation of Solution
The given equation is,
The unbalanced equation has 3hydrogen on the reactant side and 4hydrogen on the product side. To balance it, 4is multiplied on the ammonia and 3 on the fluorine on reactant side and 3 is multiplied on the ammonium fluoride on the product side.
The balanced equation is,
(f)
Interpretation:
To balance the given chemical equation.
Concept Introduction:
Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.
![Check Mark](/static/check-mark.png)
Answer to Problem 75AP
Explanation of Solution
The given equation is,
The unbalanced equation has 2silver on the reactant side and 1 silver on the product side. To balance it, 2is multiplied on the silver on the product side.
The balanced equation is,
(g)
Interpretation:
To balance the given chemical equation.
Concept Introduction:
Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.
![Check Mark](/static/check-mark.png)
Answer to Problem 75AP
Explanation of Solution
The given equation is,
The unbalanced equation has 2oxygen on the reactant side and 3 oxygen on the product side. To balance it, 3is multiplied on the oxygenon reactant side and 2 is multiplied on the trioxygenon the product side
The balanced equation is,
(h)
Interpretation:
To balance the given chemical equation.
Concept Introduction:
Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.
![Check Mark](/static/check-mark.png)
Answer to Problem 75AP
Explanation of Solution
The given equation is,
The unbalanced equation has 9 sulphur on the reactant side and 2sulphur on the product side. To balance it, 8is multiplied on the Sodium sulfiteon reactant side and 8 is multiplied on the Sodium thiosulfateon the product side.
The balanced equation is,
Want to see more full solutions like this?
Chapter 6 Solutions
Introductory Chemistry: A Foundation
- The carbon dioxide exhaled in the breath of astronauts is often removed from the spacecraft by reaction with lithium hydroxide 2LiOH(s)+CO2(g)Li2CO3(s)+H2O(l) Estimate the grams of lithium hydroxide required per astronaut per day. Assume that each astronaut requires 2.50 103 kcal of energy per day. Further assume that this energy can be equated to the heat of combustion of a quantity of glucose, C6H12O6, to CO2(g) and H2O(l). From the amount of glucose required to give 2.50 103 kcal of heat, calculate the amount of CO2 produced and hence the amount of LiOH required. The H for glucose(s) is 1273 kJ/mol.arrow_forwardEthanol, C2H5OH, is a gasoline additive that can be produced by fermentation of glucose. C6H12O62C2H5OH+2CO2 (a) Calculate the mass (g) of ethanol produced by the fermentation of 1.000 lb glucose. (b) Gasohol is a mixture of 10.00 mL ethanol per 90.00 mL gasoline. Calculate the mass (in g) of glucose required to produce the ethanol in 1.00 gal gasohol. Density of ethanol = 0.785 g/mL. (c) By 2022, the U. S. Energy Independence and Security Act calls for annual production of 3.6 1010 gal of ethanol, no more than 40% of it produced by fermentation of corn. Fermentation of 1 ton (2.2 103 lb) of corn yields approximately 106 gal of ethanol. The average corn yield in the United States is about 2.1 105 lb per 1.0 105 m2. Calculate the acreage (in m2) required to raise corn solely for ethanol production in 2022 in the United States.arrow_forwardAssume that the radius of Earth is 6400 km, the crust is 50. km thick, the density of the crust is 3.5 g/cm3, and 25.7% of the crust is silicon by mass. Calculate the total mass of silicon in the crust of Earth.arrow_forward
- The balanced equation for the reduction of iron ore to the metal using CO is Fe2O3(s) + 3 CO(g) 2 Fe(s) + 3 CO2(g) (a) What is the maximum mass of iron, in grams, that can be obtained from 454 g (1.00 lb) of iron(III) oxide? (b) What mass of CO is required to react with 454 g cot Fe2O3?arrow_forwardWhat mass of solid NaOH (97.0% NaOH by mass) is required to prepare 1.00 L of a 10.0% solution of NaOH by mass? The density of the 10.0% solution is 1.109 g/mL.arrow_forwardIron oxide ores, commonly a mixture of FeO and Fe2O3, are given the general formula Fe3O4. They yield elemental iron when heated to a very high temperature with either carbon monoxide or elemental hydrogen. Balance the following equations for these processes: Fe3O4(s)+H2(g)Fe(s)+H2O(g)Fe3O4(s)+CO(g)Fe(s)+CO2(g)arrow_forward
- Silicon is produced for the chemical and electronics industries by the following reactions. Give the balanced equation for each reaction. a. SiO2(s)+C(s)arefurnaceElectricSi(s)+CO(g) b. Liquid silicon tetrachloride is reacted with very pure solid magnesium, producing solid silicon and solid magnesium chloride. c. Na2SiF6(s) + Na(s) Si(s) + NaF(s)arrow_forwardThe present average concentration (mass percent) of magnesium ions in seawater is 0.13%. A chemistry textbook estimates that if 1.00 × 108 tons Mg were taken out of the sea each year, it would take one million years for the Mg concentration to drop to 0.12%. Do sufficient calculations to either verify or refute this statement. Assume that Earth is a sphere with a diameter of 8000 mi, 67% of which is covered by oceans to a depth of 1 mi, and that no Mg is washed back into the oceans at any time.arrow_forwardWithout consulting your textbook, list and explain the main postulates of the kinetic molecular theory for gases. How do these postulates help us account for the following bulk properties of a gas: the pressure of the gas and why the pressure of the gas increases with increased temperature; the fact that a gas tills its entire container; and the fact that the volume of a given sample of gas increases as its temperature is increased.arrow_forward
- The final step in the manufacture of platinum metal (for use in automotive catalytic converters and other products) is the reaction 3 (NH4)2PtCl6(s) 3 Pt(s) + 2 NH4Cl(s) + 2 N2(g) + 16 HCl(g) Complete this table of reaction quantities for the reaction of 12.35 g (NH4)2PtCl6.arrow_forwardExperiments show that propionic acid (CH3CH2COOH) is a weak acid. Write the chemical equation.arrow_forwardOne of the few industrial-scale processes that produce organic compounds electrochemically is used by the Monsanto Company to produce1,4-dicyanobutane. The reduction reaction is 2CH2CHCH+2H++2eNC(CH2)4CN The NC(CH2)4CN is then chemically reduced using hydrogen gas to H2N(CH2)6NH2, which is used in the production of nylon. What current must be used to produce 150.kg NC(CH2)4CN per hour?arrow_forward
- Principles of Modern ChemistryChemistryISBN:9781305079113Author:David W. Oxtoby, H. Pat Gillis, Laurie J. ButlerPublisher:Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781285199030Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305079113/9781305079113_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781285199030/9781285199030_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781133109655/9781133109655_smallCoverImage.jpg)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337399074/9781337399074_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781133949640/9781133949640_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305957404/9781305957404_smallCoverImage.gif)