Chapter 6, Problem 75AP

(a)

Interpretation Introduction

Interpretation:

To balance the given chemical equation.

Concept Introduction:

Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.

Answer to Problem 75AP

$\text{S}\text{i}\text{C}{\text{l}}_4(l)+2\text{M}\text{g}(s)\to \text{S}\text{i}(s)+2\text{M}\text{g}\text{C}{\text{l}}_2(s)$ is the balanced equation.

Explanation of Solution

$$ The given equation is,

$\text{S}\text{i}\text{C}{\text{l}}_4(l)+\text{M}\text{g}(s)\to \text{S}\text{i}(s)+\text{M}\text{g}\text{C}{\text{l}}_2(s)$

The unbalanced equation has 4 chlorine on the reactant side and two chlorine on the product side. To balance it, 2 is multiplied on the magnesium on both the sides.

The balanced equation is given as,

$\text{S}\text{i}\text{C}{\text{l}}_4(l)+2\text{M}\text{g}(s)\to \text{S}\text{i}(s)+2\text{M}\text{g}\text{C}{\text{l}}_2(s)$.

Interpretation Introduction

(b)

Interpretation:

To balance the given chemical equation.

Concept Introduction:

Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.

Answer to Problem 75AP

The balanced equation is $2\text{N}\text{O}(g)+\text{C}{\text{l}}_2(g)\to 2\text{N}\text{O}\text{C}\text{l}(g)$.

Explanation of Solution

The given equation is,

$\text{N}\text{O}(g)+\text{C}{\text{l}}_2(g)\to \text{N}\text{O}\text{C}\text{l}(g)$

The unbalanced equation has 2 chlorine on the reactant side and 1 chlorine on the product side. To balance it, 2 is multiplied on the nitrogen oxide on reactant side and 2 is multiplied on the nitrosyl chloride on the product side.

The balanced equation is

$2\text{N}\text{O}(g)+\text{C}{\text{l}}_2(g)\to 2\text{N}\text{O}\text{C}\text{l}(g)$.

Interpretation Introduction

(c)

Interpretation:

To balance the given chemical equation.

Concept Introduction:

Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.

Answer to Problem 75AP

$3\text{M}\text{n}{\text{O}}_2(s)+4\text{A}\text{l}(s)\to 3\text{M}\text{n}(s)+2\text{A}{\text{l}}_2{\text{O}}_3(s)$.

Explanation of Solution

The given equation is,

$\text{M}\text{n}{\text{O}}_2(s)+\text{A}\text{l}(s)\to \text{M}\text{n}(s)+\text{A}{\text{l}}_2{\text{O}}_3(s)$

The unbalanced equation has 2oxygen on the reactant side and 3 oxygen on the product side. To balance it, 3 is multiplied on the manganese dioxide and 4 on the aluminum on the reactant and on product side 3 is multiplied on the manganese and 2 on the aluminum oxide on the product side.

The balanced equation is,

$3\text{M}\text{n}{\text{O}}_2(s)+4\text{A}\text{l}(s)\to 3\text{M}\text{n}(s)+2\text{A}{\text{l}}_2{\text{O}}_3(s)$.

Interpretation Introduction

(d)

Interpretation:

To balance the given chemical equation.

Concept Introduction:

Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.

Answer to Problem 75AP

$16\text{C}\text{r}+3{\text{S}}_8\to 8\text{C}{\text{r}}_2{\text{S}}_3$.

Explanation of Solution

The given equation is,

$\text{C}\text{r}+{\text{S}}_8\to \text{C}{\text{r}}_2{\text{S}}_3$

The unbalanced equation has 8sulphur on the reactant side and 3 sulphur on the product side. To balance it, 16is multiplied on the chromium and 3 on the octasulphur on reactant side and 8 is multiplied on the Chromium sulfide on the product side.

The balanced equation is,

$16\text{C}\text{r}+3{\text{S}}_8\to 8\text{C}{\text{r}}_2{\text{S}}_3$.

Interpretation Introduction

(e)

Interpretation:

To balance the given chemical equation.

Concept Introduction:

Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.

Answer to Problem 75AP

$4\text{N}{\text{H}}_3+3{\text{F}}_2 \to 3\text{N}{\text{H}}_4{\text{F+NF}}_3$.

Explanation of Solution

The given equation is,

$\text{N}{\text{H}}_3+{\text{F}}_2 \to \text{N}{\text{H}}_4{\text{F+NF}}_3$

The unbalanced equation has 3hydrogen on the reactant side and 4hydrogen on the product side. To balance it, 4is multiplied on the ammonia and 3 on the fluorine on reactant side and 3 is multiplied on the ammonium fluoride on the product side.

The balanced equation is,

$4\text{N}{\text{H}}_3+3{\text{F}}_2 \to 3\text{N}{\text{H}}_4{\text{F+NF}}_3$.

Interpretation Introduction

(f)

Interpretation:

To balance the given chemical equation.

Concept Introduction:

Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.

Answer to Problem 75AP

$\text{A}{\text{g}}_2\text{S}(s)+{\text{H}}_2(g)\to 2\text{A}\text{g}(s)+{\text{H}}_2\text{S}(g)$.

Explanation of Solution

The given equation is,

$\text{A}{\text{g}}_2\text{S}(s)+{\text{H}}_2(g)\to \text{A}\text{g}(s)+{\text{H}}_2\text{S}(g)$

The unbalanced equation has 2silver on the reactant side and 1 silver on the product side. To balance it, 2is multiplied on the silver on the product side.

The balanced equation is,

$\text{A}{\text{g}}_2\text{S}(s)+{\text{H}}_2(g)\to 2\text{A}\text{g}(s)+{\text{H}}_2\text{S}(g)$.

Interpretation Introduction

(g)

Interpretation:

To balance the given chemical equation.

Concept Introduction:

Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.

Answer to Problem 75AP

$3{\text{O}}_2(g)\to 2{\text{O}}_3(g)$.

Explanation of Solution

The given equation is,

${\text{O}}_2(g)\to {\text{O}}_3(g)$

The unbalanced equation has 2oxygen on the reactant side and 3 oxygen on the product side. To balance it, 3is multiplied on the oxygenon reactant side and 2 is multiplied on the trioxygenon the product side

The balanced equation is,

$3{\text{O}}_2(g)\to 2{\text{O}}_3(g)$.

Interpretation Introduction

(h)

Interpretation:

To balance the given chemical equation.

Concept Introduction:

Balancing a chemical equation is important to make the equation follow the conservation mass of law. The atoms in the chemical reaction from the reactant side is equal to the atoms in the product side.

Answer to Problem 75AP

$8\text{N}{\text{a}}_2\text{S}{\text{O}}_3(aq)+{\text{S}}_8(s)\to 8\text{N}{\text{a}}_2{\text{S}}_2{\text{O}}_3(aq)$.

Explanation of Solution

The given equation is,

$\text{N}{\text{a}}_2\text{S}{\text{O}}_3(aq)+{\text{S}}_8(s)\to \text{N}{\text{a}}_2{\text{S}}_2{\text{O}}_3(aq)$

The unbalanced equation has 9 sulphur on the reactant side and 2sulphur on the product side. To balance it, 8is multiplied on the Sodium sulfiteon reactant side and 8 is multiplied on the Sodium thiosulfateon the product side.

The balanced equation is,

$8\text{N}{\text{a}}_2\text{S}{\text{O}}_3(aq)+{\text{S}}_8(s)\to 8\text{N}{\text{a}}_2{\text{S}}_2{\text{O}}_3(aq)$.