![Introductory Chemistry: A Foundation](https://www.bartleby.com/isbn_cover_images/9781337399425/9781337399425_largeCoverImage.gif)
Concept explainers
Balance each of the following chemical equations.
msp;
msp;
msp;
msp;
msp;
msp;
msp;
msp;
![Check Mark](/static/check-mark.png)
(a)
Interpretation:
The given chemical equation is to be balanced.
Concept Introduction:
In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.
Answer to Problem 39QAP
Explanation of Solution
The provided reaction is:
If we place a coefficient of 2 before KCl in the product side as there is already two potassium on the reactant side, then we have a balanced equation. All the other atoms are balanced and need not require any coefficients. The balancing equation is given as follows,
![Check Mark](/static/check-mark.png)
(b)
Interpretation:
The given chemical equation is to be balanced.
Concept Introduction:
In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.
Answer to Problem 39QAP
Explanation of Solution
The given unbalanced equation is:
All the atoms are balanced such as two hydrogen, one oxygen and one iron in the given equation and so it requires no coefficients on either side. Thus, the balanced chemical reaction is as follows:
![Check Mark](/static/check-mark.png)
(c)
Interpretation:
The given chemical equation is to be balanced.
Concept Introduction:
In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.
Answer to Problem 39QAP
Explanation of Solution
The given unbalanced equation is:
All the atoms are balanced in the given equation with one sodium, two hydrogen and five oxygen atoms and so no balance is required on either side of the equation. Thus, the balanced chemical reaction is as follows:
![Check Mark](/static/check-mark.png)
(d)
Interpretation:
The given chemical equation is to be balanced.
Concept Introduction:
In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.
Answer to Problem 39QAP
Explanation of Solution
The provided equation is:
Coefficient 3 should be inserted before MgO on the product side, coefficient 2 before the manganese Mn on the product side, and coefficient 3 before magnesium Mg on the reactant side to balance the equation. Thus, the balanced chemical reaction is as follows:
![Check Mark](/static/check-mark.png)
(e)
Interpretation:
The given chemical equation is to be balanced.
Concept Introduction:
In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.
Answer to Problem 39QAP
Explanation of Solution
The provided equation is:
The most complicated molecule is KH2 PO4 because it contains the greatestnumber of elements. If we place a coefficient of 2 before KOH on the reactant side and a coefficient of 2 before H2 O on the product side, it gives two atoms of potassium, four atoms of hydrogen, six atoms of oxygen and one atom of phosphorous, the balanced chemical reaction is as follows:
![Check Mark](/static/check-mark.png)
(f)
Interpretation:
The given chemical equation is to be balanced.
Concept Introduction:
In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.
Answer to Problem 39QAP
Explanation of Solution
The provided reaction is:
If we place a coefficient of 2 before H2 O anda coefficient of 4 before HNO3 we get
And we place a coefficient of 4 before NO2.
Now, we have a balanced equation.
![Check Mark](/static/check-mark.png)
(g)
Interpretation:
The given chemical equation is to be balanced.
Concept Introduction:
In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.
Answer to Problem 39QAP
Explanation of Solution
The provided reaction is:
If we place a coefficient of 2 before BaO2, 2 before H2 O on the product side and 2 before Ba(OH)2 on the reactant side that the equation will be balanced. And we have a balanced equation.
![Check Mark](/static/check-mark.png)
(h)
Interpretation:
The given chemical equation is to be balanced.
Concept Introduction:
In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.
Answer to Problem 39QAP
Explanation of Solution
The provided reaction is:
We should start by balancing H by placing a coefficient of 3 before H2 O and 2 before NH3.
We can balance NO by adding a coefficient of 2 before NO,
Now to balance oxygen, we should place 5 before O2, 6 before H2 O, 4 before NO and 4 before NH3. Now, we have a balanced equation.
Want to see more full solutions like this?
Chapter 6 Solutions
Introductory Chemistry: A Foundation
- Complete each of these reactions by filling in the blanks. Predict whether each reaction is product-favored or reactant-favored, and explain your reasoning. (a) (aq)+HSO4(aq)HCN(aq)+SO42(aq) (b) H2S (aq) + H2O() H3O+(aq) + _____ (aq) (c) H(aq) + H2O() OH(aq) +_____ (g)arrow_forwardWrite a chemical equation for each process and classify each as reactant-favored or product-favored. (a) A puddle of water evaporates on a summer day. (b) Silicon dioxide (sand) decomposes to the elements Silicon and oxygen. (c) Paper, which is mainly cellulose (C6H10O5)n, bums at a temperature of 451 F. (d) A pinch of sugar dissolves in water at room temperature.arrow_forwardWet limestone is used to scrub SO2 gas from the exhaust gases of power plants. One possible reaction gives hydrated calcium sulfite: CaCO3(s) + SO2(g) + H2O() CaSO3 H2O(s) + CO2(g) Another reaction gives hydrated calcium sulfate: CaCO3(s) + SO2(g) + H2O() + O2(g) CaSO4 H2O(s) + CO2(g) (a) Which reaction is more product-favored at equilibrium? Use the data in the table below and any other information needed in Appendix L to calculate rG for each reaction at 25 C. (b) Calculate rG for the reaction CaSO3 H2O(s) + O2(g) CaSO4 H2O(s) Is this reaction product- or reactant-favored at equilibrium?arrow_forward
- Actually, the carbon in CO2(g) is thermodynamically unstable with respect to the carbon in calcium carbonate(limestone). Verify this by determining the standardGibbs free energy change for the reaction of lime,CaO(s), with CO2(g) to make CaCO3(s).arrow_forwardShould heat be added as a reactant or as a product to each of the following equations for chemical reactions based on the given thermicity for the reaction? a. 2SO2 + O2 2SO3 (exothermic) b. N2 + O2 2NO (endothermic) c. CH4 + 2O2 CO2 + 2H2O (exothermic) d. 2H2O + 2Cl2 4HCl + O2 (endothermic)arrow_forwardUse the appropriate tables to calculate H for (a) the reaction between copper(II) oxide and carbon monoxide to give copper metal and carbon dioxide. (b) the decomposition of one mole of methyl alcohol (CH3OH) to methane and oxygen gases.arrow_forward
- Sodium chloride is added to water (at 25C) until it is saturated. Calculate the Cl concentration in such a solution. Species G(kJ/mol) NaCl(s) 384 Na+(aq) 262 Cl(aq) 131arrow_forwardShould heat be added as a reactant or as a product to each of the following equations for chemical reactions based on the given thermicity for the reaction? a. H2 + Cl2 2HCl (exothermic) b. 4NO + 6H2O 4NH3 + 5O2 (endothermic) c. 2H2O + 2Cl2 4HCl + O2 (endothermic) d. 2H2O 2H2 + O2 (exothermic)arrow_forward12.67 Hydrofluoric acid is a weak acid used in the building industry to etch patterns into glass for elegant windows. Because it dissolves glass, it is the only inorganic acid that must be stored in plastic containers. A 0.1 M solution of HF has a pH of 2.1. Calculate [Hj0"| in this solution.arrow_forward
- When 7.11 g NH4NO3 is added to 100 mL water, the temperature of the calorimeter contents decreases from 22.1 C to 17.1 C. Assuming that the mixture has the same specific heat as water and a mass of 107 g, calculate the heat q. Is the dissolution of ammonium nitrate exothermic or endothermic?arrow_forwardWhen a mixture of hydrogen and bromine is maintained at normal atmospheric pressure and heated above 200. °C in a closed container, the hydrogen and bromine react to form hydrogen bromide and a gas-phase equilibrium is established. Write a balanced chemical equation for the equilibrium reaction. Use bond enthalpies from Table 6.2 ( Sec. 6-6b) to estimate the enthalpy change for the reaction. Based on your answers to parts (a) and (b), which is more important in determining the position of this equilibrium, the entropy effect or the energy effect? In which direction will the equilibrium shift as the temperature increases above 200. °C? Explain. Suppose that the pressure were increased to triple its initial value. In which direction would the equilibrium shift? Why is the equilibrium not established at room temperature?arrow_forwardWhat is Hrxn for reaction of iron(III) oxide and carbon monoxide to give iron metal and carbon dioxide gas? Use the following reactions: 4Fe(s)+3O2(g)2Fe2O3(s)H=1648.4kJ4CO(g)+O2(g)2CO3(g)H=565.98kJarrow_forward
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningGeneral, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9780534420123/9780534420123_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781285853918/9781285853918_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305580343/9781305580343_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337399074/9781337399074_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781133949640/9781133949640_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781285199047/9781285199047_smallCoverImage.gif)