0.1 0.9 0.8 0.7 0.6 0.5 Normalized Intensity 0.2 0.3 0.4 +8.85 8.42 2442 8.42 1.0 8.40 8.40 8.38 8.36 -7.68 -7.66 \-7.64 -7.28 0 0.91 1.91 1.05 0.07 E 9.0 8.5 8.0 7.5 7.0 6.5 6.0 5.5 1 2 No. (ppm) Value 9557..2.272.00000000 3740..4.083.42916417 Absolute Value Non-Negative Value 2.29385236e+10 2.00000000 3.93299804e+10 3.42916417 3 1821..7.330.07072949 8.11214976e+8 0.07072949 4 5771..7.741.05155361 1.20605430e+10 1.05155361 5 2766. 8.461.90670753 2.18685276e+10 1.90670753 O₂N. B 6 7623.. 8.890.90908062 1.04264837e+10 0.90908062 C D 5.0 Chemical Shift (ppm) 3.99 3.92 3.98 3.92 -3.80 3.80 3.49 3.43 -2.17 4.5 4.0 3.5 3.0 2.5 2.0 1.5 1.0 E A 2.00 Normalized Intensity 0.95 0.90 2л 6' 0.85 0.80 0.75 0.70 0.65 0.60 0.55 0.50 0.45 0.40 0.35 0.30 0.25 0.20 0.15 0.10 0.05 0 168 160 152 144 136 128 120 112 104 96 J 88 Chemical Shift (ppm) 8 сосе 80 72 64 56 99 48 40 32 24 16

0.1 0.9 0.8 0.7 0.6 0.5 Normalized Intensity 0.2 0.3 0.4 +8.85 8.42 2442 8.42 1.0 8.40 8.40 8.38 8.36 -7.68 -7.66 \-7.64 -7.28 0 0.91 1.91 1.05 0.07 E 9.0 8.5 8.0 7.5 7.0 6.5 6.0 5.5 1 2 No. (ppm) Value 9557..2.272.00000000 3740..4.083.42916417 Absolute Value Non-Negative Value 2.29385236e+10 2.00000000 3.93299804e+10 3.42916417 3 1821..7.330.07072949 8.11214976e+8 0.07072949 4 5771..7.741.05155361 1.20605430e+10 1.05155361 5 2766. 8.461.90670753 2.18685276e+10 1.90670753 O₂N. B 6 7623.. 8.890.90908062 1.04264837e+10 0.90908062 C D 5.0 Chemical Shift (ppm) 3.99 3.92 3.98 3.92 -3.80 3.80 3.49 3.43 -2.17 4.5 4.0 3.5 3.0 2.5 2.0 1.5 1.0 E A 2.00 Normalized Intensity 0.95 0.90 2л 6' 0.85 0.80 0.75 0.70 0.65 0.60 0.55 0.50 0.45 0.40 0.35 0.30 0.25 0.20 0.15 0.10 0.05 0 168 160 152 144 136 128 120 112 104 96 J 88 Chemical Shift (ppm) 8 сосе 80 72 64 56 99 48 40 32 24 16

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter2: Basic Statistical Analysis With Excel

Section: Chapter Questions

Problem 12P

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In the technique of high performance liquid chromatography (HPLC) the peak area response for a particular analyte is directly proportional to concentration Analgesic tablets typically consist of aspirin and caffeine as the active ingredients, the remainder made up of inert binding material. The concentrations of aspirin and caffeine may be routinely monitored using HPLC, whereby the peak areas obtained from a solution of the tablet are compared with those obtained from standard solutions of the analytes. In an analysis to determine the concentration of caffeine in such a tablet, the following data were recorded: Solutions Analysed: Tablet Sample: Mass of tablet (dissolved in 250 cm methano): 0.523 g Caffeine Standard: Mass of caffeine (diessolved in 500 cm methanol) 0.105 g HPLC results: Solution Peak Area (catfeine) 1. Tablet Sample 325 2. Caffeine Std. 865 The concentration of caffeine in the tablet (expressed as a mass (w/wl percentage) was Oa 1.89 Ob 13.4 O 3.77 Od. 267 Oe 7.54 You…
Sample IdentificationCodeConcentration of M%TA=2-log(%T)Q50004.00 x 10-417.90.75Q50013.20 x 10-425.00.6Q50022.40 x 10-435.70.46Q50031.60 x 10-450.20.3Q50048.000 x 10-570.80.15SampleIdentificationCode%TA=2-log(%T)AMQ0210150143.70.359518560.360.000192Q0210150244.10.355561410.360.00018Q0210150343.80.358525890.360.00017Q0210150444.10.355561410.360.00018Q0210150543.80.358525890.360.00017What was their percent error?43%Does Batch 021015 meet legal requirements?No, because it is not between 2.85 * 10(4) and 3.15 * 10(4)Well #DropsBluedye1234567891012345678910Drops 9Distilled water876543210Concne 0.26tration0.52Test Tube #0.781.041.3Solutions3Concentration (M)2.082.32.6Concentration (ppm)1:1 dilution11.82Starting Dilution21.562:1 dilution0A.Zero standard0Was your calibration curve as linear as you expected?B.Did you experience any â€œdriftâ€ of the resistance readings?C.What is the equation of your best-fit line?D.What commercial drink did you analyze?E.Assuming…
I need step by step process solving [4.184x156(Tf-295)] + [4.184x85.2(Tf-368)] = 0. because my work is wrong. Thank you!!
j8P3jH-IQs_dp5pR4ENzvdYC-70kXyMz36BqJhw3sVPfBxMaZmh3VAdOl15aFtsHtwY9DBTUk4n818JEN-OWHIZVK39yT1iQorCn2ao?loBw7QYjlbavbSPXtx- egin | Student Veri. Hb Logout MyProgrammingLab Imported From IE ITEC2110:Summer2... TunesToTube - Upl. O Web Development.. O KINETICS AND EQUILIBRIUM Cla Using a second-order Integrated rate law to find concentration c.. -1 At a certain temperature this reaction follows second-order kinetics with a rate constant of 16.0 M s t: CICH,CH,C1 (g) → CH,CHCI (g) +HC1 (g) Suppose a vessel contains CICH, CH,Cl at a concentration of 1.46 M. Calculate the concentration of CICH,CH, Cl in the vessel 0.670 seconds later. You may assumne no other reaction is important. Round your answer to 2 significant digits.
ALEKS - Jacqueline Hoppenrey x G convert mg to g - Google Searc x A www-awn.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IQiHqRdYV 6Ux63Syp.JXz0Coxvwqgg4JkWI72X79QvOLp9_7U27sYQhkaocvdwecGvsUzo65uy3F6spORRg1XSqgh81is O STOICHIOMETRY Using molarity to find solute mass and solution volume Jacqueline A chemist adds 55.0 mL of a 4.75M silver perchlorate (AGCIO,) solution to a reaction flask. Calculate the mass in grams of silver perchlorate the chemist has added to the flask. Round your answer to 3 significant digits. Explanation Check Privacy Accessibil 2021 McGraw-Hill Education All Rights Reserved Terms of Use
Com X Bb Mas X Mas X Hom X K! Kahx Exan X K! Kah X Mitc X КI Kah X K Kah x K! Kah x Kah x K Kahx C session.masteringchemistry.com/myct/itemView?assignmentProblemID=134214560 Apps New Tab Effect of Salinity on... Sleep Disorders | M... P Philo American Journal ... Zeeshan JBAS Ic Wait for Next Quest... oramge juice Effect c
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Phase change properties of pure substances Cu C6H12 C (C6H5CH₂)₂0 (CH3CH₂)20 CH3CH₂OH (CH₂OH)2 NH₂COH Au C C6H14 H₂ copper cyclohexane diamond dibenzyl ether diethyl ether ethanol ethylene glycol formamide gold graphite hexane hydrogen 1084.62 6.7 4440 1.8 -116.22 -114.14 -13.0 2.57 1064.18 4489 -95.27 -259.16 2560 80.7 298 34.4 78.24 197.5 217 2836 3825 68.72 -252.879 0.385 1.841 0.51 2.369 2.438 2.394 2.389 0.129 0.709 2.27 14.304 13.26 2.68 -- 7.19 4.931 9.96 8.44 12.55 117.4 13.08 0.12 29.97 45.6 26.52 38.56 50.5 60.2 324 28.85 0.9 280.3 193.7 242 446 -- 234.4 -240.212 40.2 35.9 61.7 80 29.9 12.69
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Question: Using a method for the determination of % CaO in limestone the following results were obtained for a NIST Certified Reference Sample (CRM): % Cao 50.38, 50.20, 50.31, 50.22 50.41 Five samples were obtained from a railcar of limestone. The analysis of the samples gave the following results: % CaO 55.01, 59.61, 58.82, 64.39, 62.49 a) Determine the variance due to sampling. b) If the samples taken from the railcar had a mass of 0.500 g, what mass