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4. A new method for the determination of mercury in fish was tested against a N.I.S.T. standard to determine if there was any bias (determinate error) in the new technique. The N.I.S.T. standard fish sample was certified to contain 13.55 ppm Hg. The results of six analyses by the new method gave a mean value of 14.15 ppm and s.d. = 0.42 ppm. Does the new method give accurate results at the 95% confidence level?

4. A new method for the determination of mercury in fish was tested against a N.I.S.T. standard to determine if there was any bias (determinate error) in the new technique. The N.I.S.T. standard fish sample was certified to contain 13.55 ppm Hg. The results of six analyses by the new method gave a mean value of 14.15 ppm and s.d. = 0.42 ppm. Does the new method give accurate results at the 95% confidence level?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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4. A new method for the determination of mercury in fish was tested against a N.I.S.T. standard to determine if there was any bias (determinate error) in the new technique. The N.I.S.T. standard fish sample was certified to contain 13.55 ppm Hg. The results of six analyses by the new method gave a mean value of 14.15 ppm and s.d. = 0.42 ppm. Does the new method give accurate results at the 95% confidence level?
Transcribed Image Text:4. A new method for the determination of mercury in fish was tested against a N.I.S.T. standard to determine if there was any bias (determinate error) in the new technique. The N.I.S.T. standard fish sample was certified to contain 13.55 ppm Hg. The results of six analyses by the new method gave a mean value of 14.15 ppm and s.d. = 0.42 ppm. Does the new method give accurate results at the 95% confidence level?
Expert Solution
Step 1: Interpretation of problem statement

Given data:

The N.I.S.T standard fish sample was certified to contain 13.55 ppm

Mean value of 6 values = 14.15 ppm

s.d. =0.42 ppm

To determine:

The new method gives accurate results at 95% confidence interval

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