Explanation Given that, the buffer contains 0.040 M N a C H 3 C O 2 ( a q ) and 0.080 M C H 3 C O O H ( a q ) . The addition of a base will react with the weak acid and thus decreases the concentration of weak acid and increases the concentration of conjugate base. The proton transfer equilibrium is given below. C H 3 C O O H ( a q ) + H 2 O ( l ) ⇌ H 3 O + ( a q ) + C H 3 C O 2 − ( a q ) K a = [ H 3 O + ] [ C H 3 C O 2 − ] [ C H 3 C O O H ] = 1.8 × 10 − 5 The reaction of added base with some of C H 3 C O O H is given below. C H 3 C O O H ( a q ) + O H − ( a q ) → C H 3 C O 2 − ( a q ) + H 2 O ( l ) The initial number of moles of acid can be calculated as shown below. n ( C H 3 C O O H ) i n i t i a l = 0.300 L × 0.080 m o l . L − 1 = 0.024 m o l The molar ratio of acid and added base in the above equation is 1 : 1. The number of reacted moles of acid after addition of 0.0200 m o l o f N a O H can be calculated as given below. n ( C H 3 C O O H ) r e a c t s = 0.0200 m o l O H − × 1 m o l C H 3 C O O H 1 m o l O H − = 0.0200 m o l C H 3 C O O H Now, the remaining amount of acid can be estimated. n f i n a l = n i n i t i a l − n r e a c t s = 0

ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM

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ISBN: 9781319403959

Author: ATKINS

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Chapter 6, Problem 6G.2AST

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The pH of the resulting solution and the change in pH has to be calculated.

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Chapter 6, Problem 6G.1BST

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Chapter 6 Solutions

ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM

Ch. 6 - Prob. 6A.1AST Ch. 6 - Prob. 6A.1BST Ch. 6 - Prob. 6A.2AST Ch. 6 - Prob. 6A.2BST Ch. 6 - Prob. 6A.3AST Ch. 6 - Prob. 6A.3BST Ch. 6 - Prob. 6A.1E Ch. 6 - Prob. 6A.2E Ch. 6 - Prob. 6A.3E Ch. 6 - Prob. 6A.4E

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The p H of the resulting solution and the change in p H has to be calculated.

Solution Summary: The author explains that the pH of the resulting solution and the change in pH has to be calculated.

Interpretation:

The pH of the resulting solution and the change in pH has to be calculated.

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Chapter 6 Solutions

The p H of the resulting solution and the change in p H has to be calculated.

Solution Summary: The author explains that the pH of the resulting solution and the change in pH has to be calculated.

Interpretation: The pH of the resulting solution and the change in pH has to be calculated.

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Chapter 6 Solutions

Interpretation:

The pH of the resulting solution and the change in pH has to be calculated.