Explanation Amphiprotic: Water can accept a proton and as well as donate a proton. This is termed as “Amphiprotic” Molarity: The number of moles of solute per liter of the solution is known as “Molarity”. It is expressed.as follows: M = n V Where, n = is the number of moles of solute ‘V' is the volume of the solution in liter. Water is a weak electrolyte. So, it undergoes ionization as follows: The ionization equation can be written as, 2H 2 O (l) ⇌ H 3 O + (aq) + OH − (aq) The dissociation constant for ionization reaction is as follows: K = [ H 3 O + ] [ OH − ] [ H 2 O ] 2 (K) [ H 2 O ] 2 = [ H 3 O + ] [ OH − ] In pure water, the concentrations of H 3 O + and OH − are equal at 25 o C The concentration of unionized water is constant. So the dissociation constant equation is as follows, (K)constant = [ H 3 O + ] [ OH − ] The constant of unionized water is equal to ionic product of water. K w = [ H 3 O + ] [ OH − ] Where, K w = is the ionic product of water and is equal to 1 .0 × 10 -14 mol 2 ⋅ L -2 . Substituting the value of K w and applying the condition. Where, [ H 3 O + ] = [ OH − ] Concentration of H 3 O + is calculated as follows, 1 .0 × 10 -14 = [ H 3 O + ] 2 [ H 3 O + ] = (1

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Chapter 6, Problem 6.4E

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The amount of hydronium ions are present in 100 mL water at 25oC has to be determined.

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Chapter 6, Problem 6.3E

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ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM

Ch. 6 - Prob. 6A.1AST Ch. 6 - Prob. 6A.1BST Ch. 6 - Prob. 6A.2AST Ch. 6 - Prob. 6A.2BST Ch. 6 - Prob. 6A.3AST Ch. 6 - Prob. 6A.3BST Ch. 6 - Prob. 6A.1E Ch. 6 - Prob. 6A.2E Ch. 6 - Prob. 6A.3E Ch. 6 - Prob. 6A.4E

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The amount of hydronium ions are present in 100 mL water at 25 o C has to be determined.

Solution Summary: The author explains that water is a weak electrolyte and undergoes ionization as follows: the amount of hydronium ions present in 100 mL of water at 25

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Interpretation:

The amount of hydronium ions are present in 100 mL water at 25oC has to be determined.

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The amount of hydronium ions are present in 100 mL water at 25 o C has to be determined.

Solution Summary: The author explains that water is a weak electrolyte and undergoes ionization as follows: the amount of hydronium ions present in 100 mL of water at 25

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Interpretation: The amount of hydronium ions are present in 100 mL water at 25oC has to be determined.

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Chapter 6 Solutions

Interpretation:

The amount of hydronium ions are present in 100 mL water at 25oC has to be determined.