Chapter 6, Problem 6D.20E

Interpretation Introduction

Interpretation:

The percentage deprotonation of cation has to be calculated if $7.8\text{g}$ of ${\text{C}}_6{\text{H}}_5{\text{NH}}_{\text{3}}\text{Cl}$ is dissolved  water and make it in $\text{350}\text{m}\text{L}$ of aqueous solution.

.

Molarity:

Molarity of a solution is defined as the number of moles of solute dissolved in per liter of a solution.  This can be expressed using the given formula;

  $\text{Molarity}=\frac{\text{number}\text{of}\text{moles}}{\text{volume}\text{of}\text{solution}}$

Percentage deprotonation:

The deprotonation percentage is calculated using the ratio of concentration of cation and the initial concentration of their respective acid.  The obtained value is multiplied with 100 to get the percentage and the respective formula is given below.

  $\text{Percentage}\text{deprotonation}\text{=}\frac{\text{Concentration}\text{of}\text{cation}}{\text{Initial}\text{concentration}\text{of}\text{acid}}$