Interpretation:
The explanation for the given statement is to be provided and the way by which this answer is given for the reaction is to be shown.
Concept introduction:
Electrophiles are electron-deficient species, which has positive or partially positive charge. Lewis acids are electrophiles, which accept electron pair.
Nucleophiles are electron-rich species, which has negative or partially negative charge. Lewis bases are nucleophiles, which donate electron pair.
Substitution reaction: A reaction in which one of the hydrogen atoms of a hydrocarbon or a
Nucleophilic substitution reaction is a reaction in which an electron-rich nucleophile attacks the positive or partial positive charge of an atom or a group of atoms to replace a leaving group.
Reaction sequences involve conversion of one functional group to another, which may also require addition or loss of carbon from the reactant.
These sequences involve a number of steps carried out by different reagents. Sometimes different reagents give the same products.
An
An
The nucleophilic substitutions in which a nucleophile replaces a leaving group are known as
Cyanide ion is a much better nucleophile than ethanol.
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Organic Chemistry
- Following is a balanced equation for bromination of toluene.(a) Using the values for bond dissociation enthalpies given in Appendix 3,calculate ∆H0for this reaction.(b) Propose a pair of chain propagation steps and show that they add up to theobserved reaction.(c) Calculate ∆H0for each chain propagation step.(d) Which propagation step is rate-determininarrow_forwardWhen propenal is treated with sodium acetylide, a product is formed whose IR spectrum exhibits a broad absorption between 3200 and 3600 cm¯1, but shows no absorption near 1700 cm-1. (a) Draw the structure of the product. (b) Argue whether the nucleophile adds reversibly or irreversibly to the carbonyl group. CH HC || CH2 1. HC=CNa ? 2. NH,CIarrow_forwardWhen ethyl bromide is added to potassium tert-butoxide, the product is ethyl tert-butyl ether.(a) What happens to the reaction rate if the concentration of ethyl bromide is doubled?arrow_forward
- When ethyl bromide is added to potassium tert-butoxide, the product is ethyl tert-butyl ether. (a) What happens to the rate if the concentration of potassium tert-butoxide is tripled and the concentration of ethyl bromide is doubled?arrow_forwardAlcohols are acidic in nature. Therefore, a strong base can abstract the acidic hydrogen atom of the alcohol in a process known as deprotonation. The alcohol forms an alkoxide ion by losing the proton attached to the oxygen atom of the hydroxyl ( -OH) group. The alkoxide formed can act as a base or a nucleophile depending on the substrate and reaction conditions. However, not all bases can abstract the acidic proton of alcohols and not all alcohols easily lose the proton. Deprotonation depends on the strength of the base and the acidity of the alcohol. Strong bases, such as NaNH2, can easily abstract a proton from almost all alcohols. Likewise, more acidic alcohols lose a proton more easily. Determine which of the following reactions would undergo deprotonation based on the strength of the base and the acidity of the alcohol. Check all that apply. ► View Available Hint(s) CH3CH,OH + NH3 →CH,CH,O-NH CH3 CH3 H3C-C-H+NH3 → H3 C-C-H OH O-NH CH3CH2OH + NaNH, → CH3CH,O-Na* + NH3 CHC12 Cl₂…arrow_forwardPlease give the main substitution product for each of the following reactions, and indicate the dominant mechanism: (a) 1-bromopropane + NaOCH3 → (b) 3-bromo-3-methylpentane + NaOC2H5 →arrow_forward
- Peroxides are often added to free-radical reactions as initiators because the oxygen–oxygen bond cleaves homolytically rather easily. For example, the bond-dissociation enthalpy of the O¬O bond in hydrogen peroxide (H¬O¬O¬H) is only 213 kJ>mol (51 kcal>mol). Give a mechanism for the hydrogen peroxide-initiated reaction of cyclopentane with chlorine. The BDE for HO¬Cl is 210 kJ>mol (50 kcal>mol).arrow_forwardPleas explain how this process occurs. Identify SN1, SN2, E2, E1, nucleophiles and electrophiles.arrow_forwardCompound D, shown below, reacts with hydrogen bromide by electrophilic addition. A mixture of two organic compounds, E and F, is formed. CH3 CH₂CH₂ CH3 H compound D HBr Mixture of organic compounds E and F (i) Name the the two organic compounds E and F and show their condensed formula. (ii) Briefly explain the mechanism of the reaction between compound D and hydrogen bromide to form either compound E or compound F. (You can list/state the main steps) (iii) Which compound, E or F is the major product?arrow_forward
- The reaction of methylpropene with HBr, under radical conditions, gives two intermediates. Propose a mechanism for the formation of the two products. Propose a mechanism for the following reaction and use electronic factors to account for the formation of a major product: CH2 CH2Br N-Bromosuccinimide (NBS) ho, CCI4 Draw the structure of an antioxidant, Vitamin E free radical and use resonance structures o account for its stability.arrow_forwardRank the nucleophiles in following group in order of increasing nucleophilicity. H2O, −OH, CH3CO2-arrow_forwardAnswer the following questions regarding the nucleophilic substitution reaction shown below: CH3CH2CH2-Br + I- ------> CH3CH2CH2I + Br- (a) Write the rate law for this reaction assuming that it is a one step reaction that is first order in each of the reactants. (b) Holding the concentration of the iodide ion constant, what change would be observed in the rate if the concentration of the n- propyl bromide was tripled? (b) Assume that this is an exothermic reaction, draw the energy profile and identify the location of the transition state. (c) Draw the transition state for this reaction. (d) What change is observed for the entropy of the system during this reaction? (e) Show the likely mechanism of this reaction using the proper curved arrowsarrow_forward