Concept explainers
Analyze the motion of a simple swinging pendulum in terms of energy, (a) ignoring friction, and (b) taking friction into account. Explain why a grandfather clock has to be wound up.
(a)
The motion of a simple swinging pendulum in terms of energy ignoring friction.
Answer to Problem 12Q
Solution:The pendulum reaches at point "c" the same height
Explanation of Solution
Given:Motion in terms of energy for a simple swinging pendulumignoring friction.
If there is no friction mechanical energy can be written as:
Or
Equation (2) can be written as:
Calculation:
A diagram of situation can be shown as follows:
Suppose that the pendulum is released from point a, its energy is entirely gravitational potential
Now, when pendulum ascends to point c the kinetic energy
Conclusion: Comparing equations (4) and (5) the pendulum reaches at point " c " the same height
(b)
To DetermineThe motion of a simple swinging pendulum in terms of energy taking friction into account. Why a grandfather clock has to be wound up.
Answer to Problem 12Q
Solution:The total mechanical energy is not constant in the system, for this reason, the grandfather clock is adjusted with the help of springs to compensate for the loss of energy by friction.
Explanation of Solution
Given:Motion in terms of energy for a simple swinging pendulum taking friction into account.
Formula used: If there is friction then, equation (3) must be written as:
In this case, part of the pendulum's kinetic and potential energy is transformed into thermal energy due to friction. As the oscillations advance, the kinetic and potential energy of the system is reduced until the pendulum stops completely. In the case of the grandfather clock, the same thing happens, for this reason, the watch is adjusted with the help of springs to compensate the energy lost by friction.
Conclusion:
The total mechanical energy is not constant in the system, for this reason, the grandfather clock is adjusted with the help of springs to compensate for the loss of energy by friction.
Chapter 6 Solutions
Physics: Principles with Applications
Additional Science Textbook Solutions
Human Biology: Concepts and Current Issues (8th Edition)
Campbell Biology (11th Edition)
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
Applications and Investigations in Earth Science (9th Edition)
Cosmic Perspective Fundamentals
Chemistry: The Central Science (14th Edition)
- T1. Calculate what is the received frequency when the car drives away from the radar antenna at a speed v of a) 1 m/s ( = 3.6 km/h), b) 10 m/s ( = 36 km/h), c) 30 m /s ( = 108 km/h) . The radar transmission frequency f is 24.125 GHz = 24.125*10^9 Hz, about 24 GHz. Speed of light 2.998 *10^8 m/s.arrow_forwardNo Chatgpt please will upvotearrow_forwardNo Chatgpt please will upvotearrow_forward
- No Chatgpt pleasearrow_forward3. A measurement taken from the UW Jacobson Observatory (Latitude: 47.660503°, Longitude: -122.309424°, Altitude: 220.00 feet) when its local sidereal time is 120.00° makes the following observations of a space object (Based on Curtis Problems 5.12 + 5.13): Azimuth: 225.00° Azimuth rate: 2.0000°/s. Elevation: 75.000° Elevation rate: -0.5000°/s Range: 1500.0 km Range rate: -1.0000 km/s a. What are the r & v vectors (the state vector) in geocentric coordinates? (Answer r = [-2503.47 v = [17.298 4885.2 5.920 5577.6] -2.663]) b. Calculate the orbital elements of the satellite. (For your thoughts: what type of object would this be?) (Partial Answer e = 5.5876, 0=-13.74°) Tip: use Curtis algorithms 5.4 and 4.2.arrow_forwardConsider an isotope with an atomic number of (2(5+4)) and a mass number of (4(5+4)+2). Using the atomic masses given in the attached table, calculate the binding energy per nucleon for this isotope. Give your answer in MeV/nucleon and with 4 significant figures.arrow_forward
- A: VR= 2.4 cm (0.1 V/cm) = 0.24 V What do Vector B an C represent and what are their magnitudesarrow_forward4. Consider a cubesat that got deployed below the ISS and achieved a circular orbit of 410 km altitude with an inclination of 51.600°. What is the spacing, in kilometers, between successive ground tracks at the equator: a. Ignoring J2 (Earth's oblateness) effects b. Accounting for J2 effects c. Compare the two results and comment [Partial Answer: 35.7km difference]arrow_forwardplease solve and explainarrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON