The head of a hammer with a mass of 1.2 kg is allowed to fall onto a nail from a height of 0.50 m. What is the maximum amount of work it could do on the nail? Why do people not just “let it fall” but add their own force to the hammer as it falls?
Work done on the nail by the hammer.
Answer to Problem 2P
Solution: 5.88 J
Explanation of Solution
The work it can do on the nail is the same as what work was done to lift the hammer.
People push on the hammer to give it more energy. Since energy is the ability to do work, so more the kinetic energy provided to the hammer, it strikes the nail withmore force and the more work can be done by the hammer.
Given:
Mass of the hammer,
Height,
Formula used:
Where F is the Force required to lift the hammer
m is the mass of the hammer
a is the acceleration or gravity force
Wis the work done on the hammer
dis the height.
Calculation:
Force required lifting the hammer
Work done by the hammer
By using equation (1) and (2)
People add force because by doing so, the kinetic energy of the hammer head can be increased, and with more kinetic energy, the hammerhead can do more work.
Conclusion:Work done by hammer on the nail is 5.88 J.
Chapter 6 Solutions
Physics: Principles with Applications
Additional Science Textbook Solutions
Microbiology with Diseases by Body System (5th Edition)
Introductory Chemistry (6th Edition)
Human Physiology: An Integrated Approach (8th Edition)
Human Biology: Concepts and Current Issues (8th Edition)
Microbiology: An Introduction
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
- two satellites are in circular orbits around the Earth. Satellite A is at an altitude equal to the Earth's radius, while satellite B is at an altitude equal to twice the Earth's radius. What is the ratio of their periods, Tb/Taarrow_forwardFresnel lens: You would like to design a 25 mm diameter blazed Fresnel zone plate with a first-order power of +1.5 diopters. What is the lithography requirement (resolution required) for making this lens that is designed for 550 nm? Express your answer in units of μm to one decimal point. Fresnel lens: What would the power of the first diffracted order of this lens be at wavelength of 400 nm? Express your answer in diopters to one decimal point. Eye: A person with myopic eyes has a far point of 15 cm. What power contact lenses does she need to correct her version to a standard far point at infinity? Give your answer in diopter to one decimal point.arrow_forwardParaxial design of a field flattener. Imagine your optical system has Petzal curvature of the field with radius p. In Module 1 of Course 1, a homework problem asked you to derive the paraxial focus shift along the axis when a slab of glass was inserted in a converging cone of rays. Find or re-derive that result, then use it to calculate the paraxial radius of curvature of a field flattener of refractive index n that will correct the observed Petzval. Assume that the side of the flattener facing the image plane is plano. What is the required radius of the plano-convex field flattener? (p written as rho )arrow_forward
- 3.37(a) Five free electrons exist in a three-dimensional infinite potential well with all three widths equal to \( a = 12 \, \text{Å} \). Determine the Fermi energy level at \( T = 0 \, \text{K} \). (b) Repeat part (a) for 13 electrons. Book: Semiconductor Physics and Devices 4th ed, NeamanChapter-3Please expert answer only. don't give gpt-generated answers, & please clear the concept of quantum states for determining nx, ny, nz to determine E, as I don't have much idea about that topic.arrow_forward3.37(a) Five free electrons exist in a three-dimensional infinite potential well with all three widths equal to \( a = 12 \, \text{Å} \). Determine the Fermi energy level at \( T = 0 \, \text{K} \). (b) Repeat part (a) for 13 electrons. Book: Semiconductor Physics and Devices 4th ed, NeamanChapter-3Please expert answer only. don't give gpt-generated answers, & please clear the concept of quantum states for determining nx, ny, nz to determine E, as I don't have much idea about that topic.arrow_forwardNo chatgpt pls will upvotearrow_forward
- Use the following information to answer the next question. Two mirrors meet an angle, a, of 105°. A ray of light is incident upon mirror A at an angle, i, of 42°. The ray of light reflects off mirror B and then enters water, as shown below: Incident ray at A Note: This diagram is not to scale. a Air (n = 1.00) Water (n = 1.34) 1) Determine the angle of refraction of the ray of light in the water. Barrow_forwardHi can u please solvearrow_forward6. Bending a lens in OpticStudio or OSLO. In either package, create a BK7 singlet lens of 10 mm semi-diameter and with 10 mm thickness. Set the wavelength to the (default) 0.55 microns and a single on-axis field point at infinite object distance. Set the image distance to 200 mm. Make the first surface the stop insure that the lens is fully filled (that is, that the entrance beam has a radius of 10 mm). Use the lens-maker's equation to calculate initial glass curvatures assuming you want a symmetric, bi-convex lens with an effective focal length of 200 mm. Get this working and examine the RMS spot size using the "Text" tab of the Spot Diagram analysis tab (OpticStudio) or the Spd command of the text widnow (OSLO). You should find the lens is far from diffraction limited, with a spot size of more than 100 microns. Now let's optimize this lens. In OpticStudio, create a default merit function optimizing on spot size.Then insert one extra line at the top of the merit function. Assign the…arrow_forward
- No chatgpt pls will upvote Already got wrong chatgpt answer .arrow_forwardUse the following information to answer the next question. Two mirrors meet an angle, a, of 105°. A ray of light is incident upon mirror A at an angle, i, of 42°. The ray of light reflects off mirror B and then enters water, as shown below: A Incident ray at A Note: This diagram is not to scale. Air (n = 1.00) Water (n = 1.34) Barrow_forwardUse the following information to answer the next question. Two mirrors meet an angle, a, of 105°. A ray of light is incident upon mirror A at an angle, i, of 42°. The ray of light reflects off mirror B and then enters water, as shown below: A Incident ray at A Note: This diagram is not to scale. Air (n = 1.00) Water (n = 1.34) Barrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON