![EBK BASIC CHEMISTRY](https://www.bartleby.com/isbn_cover_images/8220101472335/8220101472335_largeCoverImage.jpg)
(a)
Interpretation:
The orbital diagram for boron should be drawn.
Concept Introduction:
The distribution of electrons in atom into orbitals is said to be electronic configuration. The electronic configuration for every element present in the periodic table is unique or different.
The electronic configuration is also denoted by the pictorial representations, known as orbital diagrams. Orbital diagram represents the pairing arrangement of electrons and individual orbitals. The filling of electrons in the orbital is done in the way; first the electrons are filled single in the orbital, after filling the single electron per orbital, if any electron is left in that energy level, then pairing of electrons occurs. Electrons are present with opposite spin in the orbital.
(b)
Interpretation:
The orbital diagram for aluminium should be drawn.
Concept Introduction:
The distribution of electrons in atom into orbitals is said to be electronic configuration. The electronic configuration for every element present in the periodic table is unique or different. Atomic number is equal to the number of protons, which is further equal to the number of electrons for neutral atom.
The electronic configuration is also denoted by the pictorial representations, known as orbital diagrams. Orbital diagram represents the pairing arrangement of electrons and individual orbitals. The filling of electrons in the orbital is done in the way; first the electrons are filled single in the orbital, after filling the single electron per orbital, if any electron is left in that energy level, then pairing of electrons occurs. Electrons are present with opposite spin in the orbital.
(c)
Interpretation:
The orbital diagram for phosphorus should be drawn.
Concept Introduction:
The distribution of electrons in atom into orbitals is said to be electronic configuration. The electronic configuration for every element present in the periodic table is unique or different. Atomic number is equal to the number of protons, which is further equal to the number of electrons for neutral atom.
The electronic configuration is also denoted by the pictorial representations, known as orbital diagrams. Orbital diagram represents the pairing arrangement of electrons and individual orbitals. The filling of electrons in the orbital is done in the way; first the electrons are filled single in the orbital, after filling the single electron per orbital, if any electron is left in that energy level, then pairing of electrons occurs. Electrons are present with opposite spin in the orbital.
(d)
Interpretation:
The orbital diagram for argon should be drawn.
Concept Introduction:
The distribution of electrons in atom into orbitals is said to be electronic configuration. The electronic configuration for every element present in the periodic table is unique or different. Atomic number is equal to the number of protons, which is further equal to the number of electrons for neutral atom.
The electronic configuration is also denoted by the pictorial representations, known as orbital diagrams. Orbital diagram represents the pairing arrangement of electrons and individual orbitals. The filling of electrons in the orbital is done in the way; first the electrons are filled single in the orbital, after filling the single electron per orbital, if any electron is left in that energy level, then pairing of electrons occurs. Electrons are present with opposite spin in the orbital.
![Check Mark](/static/check-mark.png)
Want to see the full answer?
Check out a sample textbook solution![Blurred answer](/static/blurred-answer.jpg)
Chapter 5 Solutions
EBK BASIC CHEMISTRY
- 2CIO2 + 20H-1 CIO31 + CIO2 + H2O Experiment [CIO2], M [OH-1], M 1 0.0500 0.100 23 2 0.100 0.100 3 0.100 0.0500 Initial Rate, M/s 0.0575 0.230 0.115 ... Given this date, calculate the overall order of this reaction.arrow_forward2 3 .(be)_[Ɔ+(be)_OI ← (b²)_IƆO+ (be)_I Experiment [1-] M 0.005 [OCI-] 0.005 Initial Rate M/min 0.000275 0.0025 0.005 0.000138 0.0025 0.0025 0.000069 4 0.0025 0.0025 0.000140 Calculate the rate constant of this reaction using the table data.arrow_forward1 2 3 4 I(aq) +OCl(aq) → IO¯¯(aq) + Cl¯(aq) Experiment [I-] M 0.005 [OCI-] 0.005 Initial Rate M/min 0.000275 0.0025 0.005 0.000138 0.0025 0.0025 Calculate the overall order of this reaction using the table data. 0.0025 0.000069 0.0025 0.000140arrow_forward
- H2O2(aq) +3 I¯(aq) +2 H+(aq) → 13(aq) +2 H₂O(l)· ••• Experiment [H2 O2]o (M) [I]o (M) [H+]。 (M) Initial rate (M/s) 1 0.15 0.15 0.05 0.00012 234 0.15 0.3 0.05 0.00024 0.3 0.15 0.05 0.00024 0.15 0.15 0.1 0.00048 Calculate the overall order of this reaction using the table data.arrow_forwardThe U. S. Environmental Protection Agency (EPA) sets limits on healthful levels of air pollutants. The maximum level that the EPA considers safe for lead air pollution is 1.5 μg/m³ Part A If your lungs were filled with air containing this level of lead, how many lead atoms would be in your lungs? (Assume a total lung volume of 5.40 L.) ΜΕ ΑΣΦ = 2.35 1013 ? atoms ! Check your rounding. Your final answer should be rounded to 2 significant figures in the last step. No credit lost. Try again.arrow_forwardY= - 0.039 (14.01) + 0.7949arrow_forward
- Suppose 1.76 g of magnesium acetate (Mg (CH3CO2)2) are dissolved in 140. mL of water. Find the composition of the resulting electrolyte solution. In particular, list the chemical symbols (including any charge) of each dissolved ion in the table below. List only one ion per row. mEq Then, calculate the concentration of each ion in dwrite the concentration in the second column of each row. Be sure you round your answers to the L correct number of significant digits. ion Add Row mEq L x 5arrow_forwardA pdf file of your hand drawn, stepwise mechanisms for the reactions. For each reaction in the assignment, you must write each mechanism three times (there are 10 reactions, so 30 mechanisms). (A) do the work on a tablet and save as a pdf., it is expected to write each mechanism out and NOT copy and paste the mechanism after writing it just once. Everything should be drawn out stepwise and every bond that is formed and broken in the process of the reaction, and is expected to see all relevant lone pair electrons and curved arrows.arrow_forwardNonearrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305957404/9781305957404_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781259911156/9781259911156_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305577213/9781305577213_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780078021558/9780078021558_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305079373/9781305079373_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781118431221/9781118431221_smallCoverImage.gif)