EBK PRECALCULUS W/LIMITS
EBK PRECALCULUS W/LIMITS
4th Edition
ISBN: 9781337516853
Author: Larson
Publisher: CENGAGE CO
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Fundamentals of Trigonometric Identities
Trigonometric Identities are the equalities that involve trigonometry functions and hold for all the values of variables given in the equation.
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Chapter 5.4, Problem 50E
To determine

Tofind:Thevalue of the trigonometric expression cot(u−v) for sinu=−725 and cosv=−45 where u and v are in quadrant III.

Expert Solution & Answer
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Answer to Problem 50E

Thevalue of the trigonometric expression cot(u−v) is −11711 .

Explanation of Solution

Given information:

The trigonometric expression is cot(u−v) . The value of sinu=−725 and cosv=−45 where u and v are in quadrant III.

Calculation:

Since, the value of u and v are in quadrant III. Let’s calculate the value of cosu and tanu in quadrant III using Pythagoras theorem.

  EBK PRECALCULUS W/LIMITS, Chapter 5.4, Problem 50E , additional homework tip 1

Calculate the base of the triangle when sinu=−725 .

  Base=(25)2−(−7)2=576=±24

Since, the values lies in quadrant III. Take the negative value of base.

Calculate the value of cosu and tanu .

  cosu=−2425tanu=724

Similar, let’s calculate the value of sinv and tanv in quadrant III using Pythagoras theorem.

  EBK PRECALCULUS W/LIMITS, Chapter 5.4, Problem 50E , additional homework tip 2

Calculate the base of the triangle when cosv=−45 .

  Base=(5)2−(−4)2=25−16=±3

Since, the values lies in quadrant III. Take the negative value of the base.

Calculate the value of sinv and tanv .

  sinv=−35tanv=34

Expand the given expression using sum formula.

  cot(u−v)=1tan(u−v)=1(tanu−tanv1+tanutanv)=1+tanutanvtanu−tanv

Substitute the values in the above expression.

  tan(u−v)=1+tanutanvtanu−tanv=(1+724⋅34)(724−34)=96+217−18=−11711

Therefore, thevalue of the trigonometric expression cot(u−v) is −11711 .

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Chapter 5.4, Problem 49E
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Chapter 5.4, Problem 51E

Chapter 5 Solutions

EBK PRECALCULUS W/LIMITS

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Fundamental Trigonometric Identities: Reciprocal, Quotient, and Pythagorean Identities; Author: Mathispower4u;https://www.youtube.com/watch?v=OmJ5fxyXrfg;License: Standard YouTube License, CC-BY