(a)
To Find: The graphing utility to create the
(a)
![Check Mark](/static/check-mark.png)
Answer to Problem 93E
The required plot is shown in Figure 1
Explanation of Solution
Given:
The given table is shown in Table 1
Table 1
Month | Chicago, C |
1 | 31.0 |
2 | 35.3 |
3 | 46.6 |
4 | 59.0 |
5 | 70.0 |
6 | 79.7 |
7 | 84.1 |
8 | 81.9 |
9 | 74.8 |
10 | 62.3 |
11 | 48.2 |
12 | 34.8 |
Calculation:
From the given table the model for the scatter plot is shown in Figure 1
Figure 1
(b)
To Find: The cosine model for the temperature.
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 93E
The required model is
Explanation of Solution
The general form for the cosine model is of the form,
Then, the amplitude of the model is,
The cosine function complete one half of the cycle between the times at which the temperature occur then, the period is,
Then, the value of
The value of d is obtained as,
Thus, the required equation for the model is,
(c)
To Find: The graph for the model and the scatter plot in the same viewing window and determine how well the model does fit the data.
(c)
![Check Mark](/static/check-mark.png)
Answer to Problem 93E
The graph is shown in Figure 2 and the model fits the graph very well.
Explanation of Solution
From the given table the model for the scatter plot is shown in Figure 2
Figure 2
The model
(d)
To Find: The overall normal daily high temperature.
(d)
![Check Mark](/static/check-mark.png)
Answer to Problem 93E
The overall daily high temperature is the average given by
Explanation of Solution
The overall daily high temperature is the average given by
(e)
To Find: The months during which the normal high temperature is above
(e)
![Check Mark](/static/check-mark.png)
Answer to Problem 93E
The temperature above
Explanation of Solution
The overall daily high temperature is the average given by
Consider the graph shown in Figure 3
Figure 3
The month in which the temperature is above
The month in which the temperature is below
Chapter 5 Solutions
EBK PRECALCULUS W/LIMITS
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