Concept explainers
(a)
To find : the maximum and minimum point of the function
(a)
Answer to Problem 80E
The maximum points of the function are
The minimum point of the function are
Explanation of Solution
Given information : Function
Concept Involved:
A maximum is a high point and a minimum is a low point over the given interval.
Graph:
Interpretation:
The graph shows, at
(b)
To find : all the solutions of the trigonometric equations in the given interval
(b)
Answer to Problem 80E
The solution to the given trigonometric equation are
Explanation of Solution
Given information : Function
Concept Involved:
Solution to a
To solve a trigonometric equation, use standard algebraic techniques (when possible) such as collecting like terms, extracting square roots, and factoring.
Our preliminary goal in solving a trigonometric equation is to isolate the trigonometric function on one side of the equation.
Calculation:
Factor the Greatest Common Factor of left side of the equation
Using the zero factor property which states that if
Solving the 1st equation and finding x values that makes it true in the interval
- By dividing -1 on both sides
- By simplifying fraction on both sides of the equation
Solving the 2nd equation and finding x values that makes it true in the interval
- By subtracting1 on both sides of the equation
- By simplifying on both sides of the equation
- By dividing 2 on both sides of the equation
- By simplifying fraction on both sides of the equation
Conclusion:
Chapter 5 Solutions
EBK PRECALCULUS W/LIMITS
- 5 Use the method of disks to find the volume of the solid that is obtained when the region under the curve y = over the interval [4,17] is rotated about the x-axis.arrow_forward3. Use the method of washers to find the volume of the solid that is obtained when the region between the graphs f(x) = √√2 and g(x) = secx over the interval ≤x≤ is rotated about the x-axis.arrow_forward4. Use cylindrical shells to find the volume of the solid generated when the region enclosed by the given curves is revolved about the x-axis. y = √√x, y = 0, y = √√3arrow_forward
- 5 4 3 21 N -5-4-3-2 -1 -2 -3 -4 1 2 3 4 5 -5+ Write an equation for the function graphed above y =arrow_forward6 5 4 3 2 1 -5 -4-3-2-1 1 5 6 -1 23 -2 -3 -4 -5 The graph above is a transformation of the function f(x) = |x| Write an equation for the function graphed above g(x) =arrow_forwardThe graph of y x² is shown on the grid. Graph y = = (x+3)² – 1. +10+ 69 8 7 5 4 9 432 6. 7 8 9 10 1 10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 -2 -3 -4 -5 -6- Clear All Draw:arrow_forward
- Sketch a graph of f(x) = 2(x − 2)² − 3 4 3 2 1 5 ས་ -5 -4 -3 -2 -1 1 2 3 4 -1 -2 -3 -4 -5+ Clear All Draw:arrow_forward5. Find the arc length of the curve y = 3x³/2 from x = 0 to x = 4.arrow_forward-6 -5 * 10 8 6 4 2 -2 -1 -2 1 2 3 4 5 6 -6 -8 -10- The function graphed above is: Concave up on the interval(s) Concave down on the interval(s) There is an inflection point at:arrow_forward
- 6 5 4 3 2 1 -6 -5 -3 -2 3 -1 -2 -3 -4 -5 The graph above is a transformation of the function x² Write an equation for the function graphed above g(x) =arrow_forward6 5 4 3 2 1 -1 -1 -2 -3 -4 A -5 -6- The graph above shows the function f(x). The graph below shows g(x). 6 5 4 3 2 1 3 -1 -2 -3 -4 -5 -6 | g(x) is a transformation of f(x) where g(x) = Af(Bx) where: A = B =arrow_forward5+ 4 3 2 1. -B -2 -1 1 4 5 -1 -2 -3 -4 -5 Complete an equation for the function graphed above y =arrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning