Concept explainers
(a)
(a)

Answer to Problem 95E
Probability for the randomly chosen all 4 calls are for medical help is approx. 0.4305.
Explanation of Solution
Given information:
81% of the incoming calls are for medical help.
4 incoming calls to the station are chosen at random.
Calculations:
Two events are independent, if the probability of occurrence of one
According to multiplication rule for independent events,
Let
A: One incoming call is for medical help
B: 4 incoming calls are for medical help
Now,
Probability for the incoming call is for medical help,
Since the incoming calls are selected at random, it would be more convenient to assume that incoming calls are independent of each other.
Thus,
For probability that 4 incoming calls are for medical help, apply multiplication rule for independent events:
Thus,
Probability for the randomly selected all 4 incoming calls are for medical help is approx. 0.4305.
(b)
Probability for at least 1 of the calls is not for medical help.
(b)

Answer to Problem 95E
Probability that at least 1 of the calls is not for medical help is 0.5695.
Explanation of Solution
Given information:
81% of the incoming calls are for medical help.
4 incoming calls to the station are chosen at random.
Calculations:
According to complement rule,
Let
B: 4 incoming calls are for medical help
Bc: None of the 4 incoming calls are for medical help
From Part (a),
We have
Probability for randomly selected all 4 incoming calls are for medical help,
We have of find the probability for at least 1 of the calls is not for medical help.
That means
None of the 4 incoming calls is for medical help.
Apply the complement rule:
Thus,
Probability that at least 1 of the calls is not for medical help is 0.5695.
(c)
Part (a) calculations may not be valid if 4 consecutive calls are chosen to the station.
(c)

Answer to Problem 95E
It is not necessary that calls are independent of each other.
Explanation of Solution
Given information:
81% of the incoming calls are for medical help.
4 incoming calls to the station are chosen at random.
Two events are independent, if the probability of occurrence of one event does not affect the probability of occurrence of other event.
According to multiplication rule for independent events,
In Part (a),
Multiplication rule for independent events has been used.
When 4 consecutive calls are chosen, there may be some possibility that occurrence of these 4 calls would be same.
That means
4 consecutive calls may be for the same accident when compared to the randomly chosen 4 calls.
Thus,
This will affect the probability for medical call if these 4 calls are about the same occurrence.
This implies
The incoming calls will be no longer independent.
Thus,
Use of the multiplication for independent events would be inappropriate.
Chapter 5 Solutions
PRACTICE OF STATISTICS F/AP EXAM
Additional Math Textbook Solutions
A First Course in Probability (10th Edition)
Elementary Statistics
Calculus: Early Transcendentals (2nd Edition)
Pre-Algebra Student Edition
Elementary Statistics: Picturing the World (7th Edition)
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