
Concept explainers
Interpretation:
The mass percent of composition of the gaseous mixture needs to be calculated.
Concept introduction:
Mass percent for any component is known as the ratio of mass of the component to the mass of all the component.
Here mA is the mass of component A, mtot is the mass of total components.
According to the
Moles are known as the ratio of mass and molar mass. Below is the formula:
Here, MM is molar mass and m is the mass.

Answer to Problem 89QAP
The composition of O2 is
Explanation of Solution
The pressure, volume and temperature of both tanks A and B is 1.38 atm, 750 ml or 0.750 L, and 25 0C respectively.
Converting the temperature from Celsius to Kelvin
Therefore, temperature in kelvin is 298 K
Both the tanks have CO2, O2 and N2 . Substituting the values in ideal gas equation and total number of moles of gases:
The total no. of moles of gases in each tank are 0.042 mol.
The mass of absorber containing CO2 from tank A is 0.114 g. The molar mass of CO2 is 44 g/mol. The mol of CO2 in each tank is:
After removal of N2 from tank B, the pressure of tank B is 1.11 atm. Now, the mol of gases remaining are:
Therefore, the total mole of CO2 and O2 in each tank is 0.034 mol
The moles of O2 and N2 are:
And
Therefore, the mole of O2 and N2 is 0.031 mol and 0.008 mol respectively.
The mass of CO2 is 0.114. The molar mass of O2 is 32 g/mol. The mol of N2 is 28 g/mol. Now the mass of O2 :
The mass of N2 would be:
Therefore, the mass of O2 is 0.99 g and mass of N2 is 0.224 g
The total mass of gases in each tank:
The total mass of gases is 1.330 g.
Now calculating the mass percent O2, N2 and CO2.
Thus, the composition of O2 is
The composition of O2 is
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Chapter 5 Solutions
CHEMISTRY:PRIN.+REACTIONS-OWLV2 ACCESS
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