Chapter 5, Problem 53QAP

Interpretation Introduction

(a)

Interpretation:

The given gases needs to be arranged in increasing speed of effusion.

Concept introduction:

According to the Graham’s law.

$\text{rate of effusion }\propto {\left(\frac{\text{1}}{\text{MM}}\right)}^{{}_{\text{1/2}}}$

Here, MM is molar mass of the gas.

Interpretation Introduction

(b)

Interpretation:

The given gases are needs to be arranged in increasing time of effusion.

Concept introduction:

According to the Graham’s law.

$\text{rate of effusion }\propto {\left(\frac{\text{1}}{\text{MM}}\right)}^{{}_{\text{1/2}}}$

Here, MM is molar mass of the gas.