CHEMISTRY:PRIN.+REACTIONS-OWLV2 ACCESS
CHEMISTRY:PRIN.+REACTIONS-OWLV2 ACCESS
8th Edition
ISBN: 9781305079298
Author: Masterton
Publisher: Cengage Learning
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Question
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Chapter 5, Problem 3QAP
Interpretation Introduction

(a)

Interpretation:

The given pressure in mm Hg needs to be converted into atm, kPa and bar.

Concept introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

The following conversion factors are used in the given case:

1 mm Hg=0.001316 atm

1 mm Hg=0.1333 kPa

And,

1 mm Hg=0.001333 bar

Interpretation Introduction

(b)

Interpretation:

The given pressure in atm needs to be converted into mm Hg, kPa and bar.

Concept introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

The following conversion factors are used in the given case:

1 mm Hg=0.001316 atm

1 mm Hg=0.1333 kPa

And,

1 mm Hg=0.001333 bar

Interpretation Introduction

(c)

Interpretation:

The given pressure in kPa needs to be converted into atm, mm Hg and bar.

Concept introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

The following conversion factors are used in the given case:

1 mm Hg=0.001316 atm

1 mm Hg=0.1333 kPa

And,

1 mm Hg=0.001333 bar

Interpretation Introduction

(d)

Interpretation:

The given pressure in bar needs to be converted into atm, kPa and mm Hg.

Concept introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

The following conversion factors are used in the given case:

1 mm Hg=0.001316 atm

1 mm Hg=0.1333 kPa

And,

1 mm Hg=0.001333 bar

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Chapter 5 Solutions

CHEMISTRY:PRIN.+REACTIONS-OWLV2 ACCESS

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