Explanation The blocks are tied by the single string therefore the tension forces acting on the blocks will be same. The forces acting on both the blocks are as shown below. The block of mass m 1 covers a distance of 1.00 m in 1.20 s with some acceleration. Write the expression for the acceleration of the block as. x = v i t + 1 2 a t 2 (I) Here, x is the distance covered, v i is the initial velocity, a is the acceleration of the block and t is the time taken by the block. The block starts to move from rest so the initial velocity of the block is zero. Write the expression for the tension in the string as. m 2 g − T = m 2 a (II) Here, T is the tension in the string, m 2 is the mass of the block and g is the acceleration due to gravity. Write the expression for the normal reaction of the block of mass m 1 as. n 1 = m 1 g (III) Here, n 1 is the normal reaction of the block and m 1 is the mass of the block. Write the expression for the static equilibrium of the block of mass m 1 as. T − μ k n 1 = m 1 a Substitute m 1 g for n 1 in above equation. T − μ k m 1 g = m 1 a (IV) Here, T is the tension in the string, μ k is the coefficient of kinetic friction, is the normal reaction of the block. Conclusion: Substitute 1.00 m for x , 0 m / s for v i and 1

Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term

9th Edition

ISBN: 9781305932302

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 5, Problem 87AP

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The coefficient of friction between the block and the table.

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Chapter 5, Problem 86AP

Chapter 5, Problem 88AP

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Example Two charges, one with +10 μC of charge, and another with - 7.0 μC of charge are placed in line with each other and held at a fixed distance of 0.45 m. Where can you put a 3rd charge of +5 μC, so that the net force on the 3rd charge is zero?

* Coulomb's Law Example Three charges are positioned as seen below. Charge 1 is +2.0 μC and charge 2 is +8.0μC, and charge 3 is - 6.0MC. What is the magnitude and the direction of the force on charge 2 due to charges 1 and 3? 93 kq92 F == 2 r13 = 0.090m 91 r12 = 0.12m 92 Coulomb's Constant: k = 8.99x10+9 Nm²/C² ✓

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Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term

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The coefficient of friction between the block and the table.

Solution Summary: The author explains the coefficient of friction between the block and the table. The tension forces acting on both the blocks are as shown.

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Chapter 5 Solutions