Chemistry: Atoms First
Chemistry: Atoms First
2nd Edition
ISBN: 9780073511184
Author: Julia Burdge, Jason Overby Professor
Publisher: McGraw-Hill Education
Question
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Chapter 5, Problem 5.67QP

(a)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

= 12.0107 amu = 1.0079 amuCl  = 35.453 amu = 14.0067 amu = 15.9994 amu = 32.065 amu

To calculate: Molecular mass of CH3Cl

(a)

Expert Solution
Check Mark

Answer to Problem 5.67QP

Molecular mass of CH3Cl=50.4874amu

Explanation of Solution

MolecularmassofCH3Cl=1(massofCinamu)+3(massofHinamu)+1(massofClinamu) =1(12.0107amu)+3(1.0079amu)+1(35.453amu) =(12.0107+3.0237+35.453)amu =50.4874amu

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula. The molecular mass of CH3Cl was found to be 50.4874amu.

(b)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

= 12.0107 amu = 1.0079 amuCl  = 35.453 amu = 14.0067 amu = 15.9994 amu = 32.065 amu

To calculate: Molecular mass of N2O4

(b)

Expert Solution
Check Mark

Answer to Problem 5.67QP

Molecular mass of N2O4=92.02894amu

Explanation of Solution

Molecular formula is given as N2O4

MolecularmassofN2O4=2(massofNinamu)+4(massofOinamu)=2(14.0067amu)+4(15.9994amu)=(28.0134+63.9976)amu=92.02894amu

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula.  The molecular mass of N2O4 was found to be 92.02894amu.

(C)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

= 12.0107 amu = 1.0079 amuCl  = 35.453 amu = 14.0067 amu = 15.9994 amu = 32.065 amu

To calculate: Molecular mass of SO2

(C)

Expert Solution
Check Mark

Answer to Problem 5.67QP

Molecular mass of SO2=64.0638amu

Explanation of Solution

Molecular formula is given as SO2

MolecularmassofSO2=1(massofSinamu)+2(massofOinamu)=1(32.065amu)+2(15.9994amu)=(32.065+31.9988)amu=64.0638amu

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula.  The molecular mass of SO2 was found to be 64.0638amu.

(d)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

= 12.0107 amu = 1.0079 amuCl  = 35.453 amu = 14.0067 amu = 15.9994 amu = 32.065 amu

To calculate: Molecular mass of C6H12

(d)

Expert Solution
Check Mark

Answer to Problem 5.67QP

Molecular mass of C6H12=84.159amu

Explanation of Solution

Molecular formula is given as C6H12

MolecularmassofC6H12=6(massofCinamu)+12(massofHinamu)=6(12.0107amu)+12(1.0079amu)=(72.0642+12.0948)amu=84.159amu

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula.  The molecular mass of C6H12 was found to be 84.159amu

(e)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

= 12.0107 amu = 1.0079 amuCl  = 35.453 amu = 14.0067 amu = 15.9994 amu = 32.065 amu

To calculate: Molecular mass of H2O2

(e)

Expert Solution
Check Mark

Answer to Problem 5.67QP

Molecular mass of H2O2=34.0146amu

Explanation of Solution

Molecular formula is given as H2O2

MolecularmassofH2O2=2(massofHinamu)+2(massofOinamu)=2(1.0079amu)+2(15.9994amu)=(2.0158+31.9988)amu=34.0146amu

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula.  The molecular mass of H2O2 was found to be 34.0146amu.

(f)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

= 12.0107 amu = 1.0079 amuCl  = 35.453 amu = 14.0067 amu = 15.9994 amu = 32.065 amu

(f)

Expert Solution
Check Mark

Answer to Problem 5.67QP

Molecular mass of C12H22O11=342.3 amu

To calculate: Molecular mass of C12H22O11

Explanation of Solution

Molecular formula is given as C12H22O11

MolecularmassofC12H22O11=12(massofCinamu)+22(massofHinamu)+11(massofOinamu)=12(12.0107amu)+22(1.0079)+11(15.9994amu)=(144.1284+22.1738+175.9934)amu=342.3 amu

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula.  The molecular mass of C12H22O11 was found to be 342.3 amu.

(g)

Interpretation Introduction

Interpretation: The molecular mass of the given substances has to be calculated.

Concept introduction: The sum of the atomic masses of all the atoms present in that molecule will give an overall mass of that molecule which is termed as Molecular mass.

Some atomic weight of atoms are,

= 12.0107 amu = 1.0079 amuCl  = 35.453 amu = 14.0067 amu = 15.9994 amu = 32.065 amu

(g)

Expert Solution
Check Mark

Answer to Problem 5.67QP

Molecular mass of NH3=17.0304amu

To calculate: Molecular mass of NH3

Explanation of Solution

Molecular formula is given as NH3

MolecularmassofNH3=1(massofNinamu)+3(massofHinamu)=1(14.0067amu)+3(1.0079amu)=(14.0067+3.0237)amu=17.0304amu

The molecular mass of the given substance was calculated using atomic weights of each elements present in its molecular formula.  The molecular mass of NH3 was found to be 17.0304amu.

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Chapter 5 Solutions

Chemistry: Atoms First

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