Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 5, Problem 5.14.2P
To determine
(a)
The design of bearing plate by LRFD.
To determine
(b)
The design of bearing plate by ASD.
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
The rectangular doubly reinforcement stress concrete block with the arrangement of reinforcement of 2N28 bars on top and 3N28 bars on bottom. The
modulus of elasticity are Ec =23,500MPa and Es = 200,000MPa. Dead load is 18KN/m and live load is 12KN/m.
f'c = 25MPa
800
730
N12 ligs (fx.t-500MPa)
Ast = 3N28
350
Span = 10m
Figure 3
Use the Transformed section approach considering the presence of steel. Calculate the concrete area and transformed steel area in both
tension and compression shown in Figure 3.
n=Es/Ec
Ast=1232mm^2
Use n-1 for the transformed area to do the calculate. Unit: mm^2 with two decimal
X = 165
Y = 40
Z = 25
D = 500
Question 8
1 p
The rectangular doubly reinforcement stress concrete block with the arrangement of reinforcement of 2N28 bars on
top and 3N28 bars on bottom. The modulus of elasticity are Ec=23,500MPa and Es = 200,000MPa. Dead load is
18KN/m and live load is 12KN/m.
f'c = 25MPa
800
TE
730
N12 ligs (fsv.t-500MPa)
Ast = 3N28
350
Span = 10m
Figure 3
Calculate the concrete stresses in tension and compression of the reinforcement concrete beam shown in
Figure 3.
Compression concrete stress
Choose ]
Tension Concrete stress
Choose]
Chapter 5 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 5 - Prob. 5.2.1PCh. 5 - Prob. 5.2.2PCh. 5 - Verify the value of Zx for a W1850 that is...Ch. 5 - Prob. 5.2.4PCh. 5 - Prob. 5.4.1PCh. 5 - Prob. 5.4.2PCh. 5 - Determine the smallest value of yield stress Fy,...Ch. 5 - Prob. 5.5.1PCh. 5 - Prob. 5.5.2PCh. 5 - Prob. 5.5.3P
Ch. 5 - Prob. 5.5.4PCh. 5 - Prob. 5.5.5PCh. 5 - Prob. 5.5.6PCh. 5 - Prob. 5.5.7PCh. 5 - Prob. 5.5.8PCh. 5 - Prob. 5.5.9PCh. 5 - If the beam in Problem 5.5-9 i5 braced at A, B,...Ch. 5 - Prob. 5.5.11PCh. 5 - Prob. 5.5.12PCh. 5 - Prob. 5.5.13PCh. 5 - Prob. 5.5.14PCh. 5 - Prob. 5.5.15PCh. 5 - Prob. 5.5.16PCh. 5 - Prob. 5.6.1PCh. 5 - Prob. 5.6.2PCh. 5 - Prob. 5.6.3PCh. 5 - Prob. 5.6.4PCh. 5 - Compute the nominal shear strength of an M107.5 of...Ch. 5 - Compute the nominal shear strength of an M1211.8...Ch. 5 - Prob. 5.8.3PCh. 5 - Prob. 5.8.4PCh. 5 - Prob. 5.10.1PCh. 5 - Prob. 5.10.2PCh. 5 - Same as Problem 5.10-2, except that lateral...Ch. 5 - Prob. 5.10.4PCh. 5 - The given beam is laterally supported at the ends...Ch. 5 - Prob. 5.10.6PCh. 5 - Prob. 5.10.7PCh. 5 - Prob. 5.11.1PCh. 5 - Prob. 5.11.2PCh. 5 - Prob. 5.11.3PCh. 5 - Prob. 5.11.4PCh. 5 - Prob. 5.11.5PCh. 5 - Prob. 5.11.6PCh. 5 - Prob. 5.11.7PCh. 5 - Prob. 5.11.8PCh. 5 - Prob. 5.11.9PCh. 5 - Prob. 5.12.1PCh. 5 - Prob. 5.12.2PCh. 5 - Prob. 5.12.3PCh. 5 - Prob. 5.13.1PCh. 5 - Prob. 5.13.2PCh. 5 - Prob. 5.14.1PCh. 5 - Prob. 5.14.2PCh. 5 - Prob. 5.14.3PCh. 5 - Prob. 5.14.4PCh. 5 - Prob. 5.15.1PCh. 5 - Prob. 5.15.2PCh. 5 - Prob. 5.15.3PCh. 5 - Prob. 5.15.4PCh. 5 - Prob. 5.15.5PCh. 5 - Prob. 5.15.6PCh. 5 - Prob. 5.15.7PCh. 5 - Same as Problem 5.15-7, except that the sag rods...
Knowledge Booster
Similar questions
- A beam has a width of 300 mm and an effective depth of 480 mm strength Pc= 34 MPa. Steel yield strength fy=415 MPa. The section is to be reinforced for tension only and the effective concrete cover is 70 mm. Deadload moment is 140 kN-m and the liveload moment is 180 kN-m. Use 2010 NSCP with t= 0.005. A. What is the governing steel ratio? B. What is the maximum number of bars needed for a 25mm diameter reinforcements? C. What is the minimum number of bars needed for a 25mm diameter reinforcements?arrow_forwardGive me right solution with clear calculationsarrow_forwardPlease show its complete solution, explanation, FBD, and units. Thank you in advance!arrow_forward
- in 21- ő A steel beam is reinforced by three steel rods. The modulous of elasticity for concrete is 20Gpa and for steel is 200Gpa. Maximum allowable stress for concrete is 9.45Mpa and for steel is 140Mpa. Calculate the largest allowable positive WBT bending moment in the beam. иа mo maod motinu od o boblow need sved Ha bus 400mm aidT (alonnerlo ert to rigiow stongi)/4000E of Trup 200-0 signs or botuesom sWnworla es berloss M bris V zsra erli owob stiW maod sdi to mergeib insm brol bus borlism tuo sallimill nollor 10 nige over on The modulus of elasticity for concrete is 20Gpa and for the steel is 200 Gpa. Allowable stress for concrete is 9Mpa and for steel is 140Mpa. Calculate the maxium allowable bending momemt that can be applied per metal rod of the concrete slab. 150mm 200mm D=16mm 140 mm -22mm Diameter TOPABA t 50mm T 140 mm 140 mm 140 mmarrow_forwardPlease solve it given the values. Show all solutionsarrow_forwardAnswer the following for the section at Point D Only Calculate the distributed load "w" that: Will cause the section crack Will cause the reinforcement to yield. Material Properties: F'c = 5000 psi Fy = 60000 psi Es = 29000000 psi Ln = 27 ft L wl₂² 16 wl,² 14 CD L wl,2 vl₁² 10 11 win² 16 h: 28 in A=4 in² b=14 in n d: 25 inarrow_forward
- 2. The A-36 steel Bar BC had a diameter of 40 mm before the two loads, P, were applied. If after loading, the new diameter of the bar is 39.995 mm, what was P? P -1 m B 0.75 m 1 marrow_forwardA rectangular beam 250 mm wide, 500 mm deep is reinforced at the bottom with d-20-mm-dismeter bars and at the top with 2-16-mm bars. Concrete cover to bar centroid at the top is M0 mm and at the bottom is 70 mm. Use concrete strength r'e-21 MPa und steel yield strength fy 415 MPa for 20- mm bars and fy= 275 MPA for 16 mm bars Detenmine the design moment capacity n kN m of the beam in negative bending. A 40.06 O45.07 C. 42.70 D47.55arrow_forwardDetails of a rectangular column are as follows: Column width along X-axis-250 mm Column Depth along the Y-axis-600 mm 8-25 mm diameter bars distributed equally along the longer sides. 10 mm diameter ties spaced at 10 mm on centers Concrete 28th day Compressive strength, fc;=20.7 MPa Reinforcing Steel yield strength, fy-415 MPa Assume that compression steel yields. a) Which of the following gives the nominal balanced load Pb (kN). A = 90.4 mm b) Which of the following gives the nominal axial load (kN) that the column n carry at an eccentricity of 200 mm along the X axis from the centroidal Y-axis.arrow_forward
- Item 2 Figure 1 A D of 1 -0.5 m- 400 KN B -0.5 m C 0.4 m Part A The assembly consists of two posts AD and CF made of A-36 steel and having a cross-sectional area of 1100 mm², and a 2014-T6 aluminum post BE having a cross-sectional area of 1700 mm². If a central load of 400 kN is applied to the rigid cap, determine the normal stress in each post. There is a small gap of 0.12 mm between the post BE and the rigid member ABC. (Figure 1) Enter your answers, separated by commas. JAD, CF, OBE = Submit O Π| ΑΣΦ ↓↑ My Answers Give Up vec ? MPa Provide Feedback Continuearrow_forwardPlease see the question below. Thank youarrow_forwardPlease show its detailed solution, explanation, FBD, and units. Thank you!arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Steel Design (Activate Learning with these NEW ti...Civil EngineeringISBN:9781337094740Author:Segui, William T.Publisher:Cengage Learning
Steel Design (Activate Learning with these NEW ti...
Civil Engineering
ISBN:9781337094740
Author:Segui, William T.
Publisher:Cengage Learning