Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Chapter 5, Problem 5.11.4P
To determine
(a)
The W shape.
To determine
(b)
The W shape.
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Details of a rectangular column are as follows:
Column width along X-axis-250 mm
Column Depth along the Y-axis-600 mm
8-25 mm diameter bars distributed equally along the longer sides.
10 mm diameter ties spaced at 10 mm on centers
Concrete 28th day Compressive strength, fc;=20.7 MPa
Reinforcing Steel yield strength, fy-415 MPa
Assume that compression steel yields.
a) Which of the following gives the nominal balanced load Pb (kN). A = 90.4 mm
b) Which of the following gives the nominal axial load (kN) that the column n carry at an
eccentricity of 200 mm along the X axis from the centroidal Y-axis.
A reinforced concrete cantilever beam is shown
below. The beam cross section is a rectangle,
12 inches deep by 18 inches wide.
Material properties are:
- Concrete weight: wt = 150 pcf
- Concrete compressive strength: f'c = 4000 psi
- Concrete tensile strength: f't = 400 psi
- Steel tensile strength: fy = 60 ksi
- Stirrup consists of #4 bar
- Beam is not exposed to weather or in contact
with soil.
Determine if the beam will crack under its own weight, if its self-weight is 250lb/ft.
10 ft
-18"
BEAM SECTION
beam will crack
beam will not crack
unknown, not enough information to calculate
A reinforced concrete cantilever beam is shown
below. The beam cross section is a rectangle,
12 inches deep by 18 inches wide.
Material properties are:
- Concrete weight: wt = 150 pcf
- Concrete compressive strength: f'c = 4000 psi
- Concrete tensile strength: f't= 400 psi
- Steel tensile strength: fy = 60 ksi
- Stirrup consists of #4 bar
- Beam is not exposed to weather or in contact
with soil.
Calculate the maximum bending moment under the beam self-weight.
10 ft-
8,750 lb-ft
10,250 lb-ft
11,250 lb-ft
11,750 lb-ft
18"
BEAM SECTION
Chapter 5 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 5 - Prob. 5.2.1PCh. 5 - Prob. 5.2.2PCh. 5 - Verify the value of Zx for a W1850 that is...Ch. 5 - Prob. 5.2.4PCh. 5 - Prob. 5.4.1PCh. 5 - Prob. 5.4.2PCh. 5 - Determine the smallest value of yield stress Fy,...Ch. 5 - Prob. 5.5.1PCh. 5 - Prob. 5.5.2PCh. 5 - Prob. 5.5.3P
Ch. 5 - Prob. 5.5.4PCh. 5 - Prob. 5.5.5PCh. 5 - Prob. 5.5.6PCh. 5 - Prob. 5.5.7PCh. 5 - Prob. 5.5.8PCh. 5 - Prob. 5.5.9PCh. 5 - If the beam in Problem 5.5-9 i5 braced at A, B,...Ch. 5 - Prob. 5.5.11PCh. 5 - Prob. 5.5.12PCh. 5 - Prob. 5.5.13PCh. 5 - Prob. 5.5.14PCh. 5 - Prob. 5.5.15PCh. 5 - Prob. 5.5.16PCh. 5 - Prob. 5.6.1PCh. 5 - Prob. 5.6.2PCh. 5 - Prob. 5.6.3PCh. 5 - Prob. 5.6.4PCh. 5 - Compute the nominal shear strength of an M107.5 of...Ch. 5 - Compute the nominal shear strength of an M1211.8...Ch. 5 - Prob. 5.8.3PCh. 5 - Prob. 5.8.4PCh. 5 - Prob. 5.10.1PCh. 5 - Prob. 5.10.2PCh. 5 - Same as Problem 5.10-2, except that lateral...Ch. 5 - Prob. 5.10.4PCh. 5 - The given beam is laterally supported at the ends...Ch. 5 - Prob. 5.10.6PCh. 5 - Prob. 5.10.7PCh. 5 - Prob. 5.11.1PCh. 5 - Prob. 5.11.2PCh. 5 - Prob. 5.11.3PCh. 5 - Prob. 5.11.4PCh. 5 - Prob. 5.11.5PCh. 5 - Prob. 5.11.6PCh. 5 - Prob. 5.11.7PCh. 5 - Prob. 5.11.8PCh. 5 - Prob. 5.11.9PCh. 5 - Prob. 5.12.1PCh. 5 - Prob. 5.12.2PCh. 5 - Prob. 5.12.3PCh. 5 - Prob. 5.13.1PCh. 5 - Prob. 5.13.2PCh. 5 - Prob. 5.14.1PCh. 5 - Prob. 5.14.2PCh. 5 - Prob. 5.14.3PCh. 5 - Prob. 5.14.4PCh. 5 - Prob. 5.15.1PCh. 5 - Prob. 5.15.2PCh. 5 - Prob. 5.15.3PCh. 5 - Prob. 5.15.4PCh. 5 - Prob. 5.15.5PCh. 5 - Prob. 5.15.6PCh. 5 - Prob. 5.15.7PCh. 5 - Same as Problem 5.15-7, except that the sag rods...
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- USE NSCP 2010 A simply supported beam is reinforced with 4 – 28 mm ø at the bottomand 2 – 28 mm ø at the top of the beam. Steel covering to centroid ofreinforcement is 70 mm at the top and bottom of the beam. The beamhas a total depth of 400 mm and a widthof 300 mm. fc’ = 30 MPa, fy = 415 MPa. Balanced steel ratio ρb = 0.031.Compute the ultimate moment capacity of the beam in kN-m. Usereduction factor of 0.90arrow_forwardI need the answer to the question in reinforced concretearrow_forwardDesign an interior span slab of a concrete floor system with the following description: Span = 30 m Imposed dead load= 900 N/m2 Live load= 4900 N/m2 fc’= 28 MPa fy = 415 MPa Note :- Solve by ACI methodarrow_forward
- X = 165 Y = 40 Z = 25 D = 500arrow_forwardA beam has a width of 300 mm and an effective depth of 480 mm strength Pc= 34 MPa. Steel yield strength fy=415 MPa. The section is to be reinforced for tension only and the effective concrete cover is 70 mm. Deadload moment is 140 kN-m and the liveload moment is 180 kN-m. Use 2010 NSCP with t= 0.005. A. What is the governing steel ratio? B. What is the maximum number of bars needed for a 25mm diameter reinforcements? C. What is the minimum number of bars needed for a 25mm diameter reinforcements?arrow_forwardProblem 1. The composite beam shown below carries a cantilevered load of 10 kN. The beam consists of one 30 x 124 mm plate and four 12 x 50 mm plates. They are pinned together at 120 mm intervals with round pins. The pin material has a shear strength of 159 MPa. Compute the minimum acceptable diameter for the pins. O O O O O O O -0 O 0- O 1000 mm Do O -120 mm (typ) O O O P = 10 KN 30 x 124 mm 12 x 50 mm (typ)arrow_forward
- The W10 × 88 column shown bears on a concrete pedestal of the same size as the square column base plate. The column load is Pu = 600 kips (LRFD) or Pa = 400 kips (ASD). The compressive strength of the concrete is 5 ksi. Section properties A = 25.9 in TIH d = 10.8 in tw = 0.605 in bf = 10.3 in tf = 0.99 in bf/2tf = 5.18 h/tw = 13.0 n (A) 15 in x 15 in × 1 in (C) 16 in x 16 in × 1 in 0.80bf B n n 0.95d N n The smallest of the following base plates that meets the design criteria is (B) 15 in x 15 in x 1.25 in (D) 16 in x 16 in × 1.25 in Material properties W10 × 88 ASTM A992 Fy = 50 ksi Fu = 65 ksi plate ASTM A572, grade 50 Fy = 50 ksi Fu = 65 ksiarrow_forwardA rectangular beam 250 mm wide, 500 mm deep is reinforced at the bottom with d-20-mm-dismeter bars and at the top with 2-16-mm bars. Concrete cover to bar centroid at the top is M0 mm and at the bottom is 70 mm. Use concrete strength r'e-21 MPa und steel yield strength fy 415 MPa for 20- mm bars and fy= 275 MPA for 16 mm bars Detenmine the design moment capacity n kN m of the beam in negative bending. A 40.06 O45.07 C. 42.70 D47.55arrow_forwardThe rectangular doubly reinforcement stress concrete block with the arrangement of reinforcement of 2N28 bars on top and 3N28 bars on bottom. The modulus of elasticity are Ec =23,500MPa and Es = 200,000MPa. Dead load is 18KN/m and live load is 12KN/m. f' = 25MPa 800 IDE 730 N12 ligs (fsv.f-500MPa) Ast = 3N28 350 Span = 10m Figure 3 Calculate the combination load for the reinforcement concrete beam shown in Figure 3. Unit: KN/m with two decimal. 1.2G+1.5Q=warrow_forward
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