Chapter 5, Problem 5.12P

Interpretation Introduction

Interpretation:

The barometric pressure $29.5$ inches of mercury should be converted into pressure in atmospheres.

Concept Introduction:

Relationship between barometric pressure and pressure in atmosphere is given as.

$\text{1}\text{.00 atm}=\text{760 mm Hg}$.

Answer to Problem 5.12P

$0.9859$ atm.

Explanation of Solution

Given information:

The barometric pressure of $29.5$ inches of mercury.

Given barometric pressure of $29.5$ inches of mercury.

First convert inches of mercury to $\text{mm}$ of mercury.

$\text{1 inch}=25.\text{4 mm}$.

Thus, $29.\text{5 in}=25.4\times 29.\text{5 mm}$.

$=749.\text{3 mm}$ of mercury.

Now, we know that, $1.00\text{a}\text{t}\text{m}=7\text{60 mm Hg}$.

Or, $76\text{0 mm of Hg}=1.0\text{0 atm}$.

Thus, $749.\text{3 mm of Hg}=\frac{1.0\text{0 atm}}{76\text{0 mm of Hg}}\times 749.3\text{m}\text{m} \text{o}\text{f} \text{H}\text{g}$.

$=0.9859\text{a}\text{t}\text{m}$.

Conclusion

Hence, the barometric pressure of $29.5$ inches of mercury is equal to $0.9859$ pressure in atmospheres.