(a)
Interpretation:
Interpret name of NaMnO4.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state name is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
(b)
Interpretation:
Interpret name of AlPO4.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state name is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
(c)
Interpretation:
Interpret name of CrCO3.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state name is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
(d)
Interpretation:
Interpret name of Ca(ClO2 )2.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state name is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
(e)
Interpretation:
Interpret name of BaCO3.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state name is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
(f)
Interpretation:
Interpret name of CaCrO4.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The name of Binary ion contains the name of cation first then proceeded the name of anion. The name of cation in Binary ion remain same to that of metal while for anion its name ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state name is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.
Want to see the full answer?
Check out a sample textbook solution
Chapter 5 Solutions
Introductory Chemistry: A Foundation
- Please correct answer and don't used hand raitingarrow_forward(a) The following synthesis of the molecule shown in the circle has a major problem. What is this problem? (2 pts) 1) HBr (no peroxides) 2) H- NaNH2 Br 3) NaNH, 4) CH3Br 5) H2, Pd (b) Starting with the molecule shown below and any other materials with two carbons or less, write out an alternate synthesis of the circled molecule. More than one step is needed. Indicate the reagent(s) and the major product in all the steps in your synthesis. (5 pts) 2024 Fall Term (1) Organic Chemistry 1 (Lec) CHEM 22204 02[6386] (Hunter College) (c) Using the same starting material as in part (b) and any other materials win two carpons or less, write out syntheses of the circled molecules shown below. More than one step is needed in each case. Indicate the reagent(s) and the major product in all the steps in your synthesis. You may use reactions and products from your synthesis in part (b). (5 pts)arrow_forwardalt ons for Free Response Questions FRQ 1: 0/5 To spectrophotometrically determine the mass percent of cobalt in an ore containing cobalt and some inert materials, solutions with known [Co?) are prepared and absorbance of each of the solutions is measured at the wavelength of optimum absorbance. The data are used to create a calibration plot, shown below. 0.90- 0.80- 0.70 0.60 0.50 0.40- 0.30 0.20- 0.10- 0.00- 0.005 0.010 Concentration (M) 0.015 A 0.630 g sample of the ore is completely dissolved in concentrated HNO3(aq). The mixture is diluted with water to a final volume of 50.00 ml. Assume that all the cobalt in the ore sample is converted to Co2+(aq). a. What is the [Co2] in the solution if the absorbance of a sample of the solution is 0.74? 13 ✗ b. Calculate the number of moles of Co2+(aq) in the 50.00 mL solution. 0.008 mols Coarrow_forward
Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning