
(a)
Interpretation:
Interpret formula of Copper(i) iodide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR
The formula of given compound is CuI.
Explanation of Solution
Copper(i) is denoted as Cu+ while iodide denoted as I- and thus formula of given compound is CuI.
(b)
Interpretation:
Interpret formula of Cobaltous chloride.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR
The formula of given compound is CoCl2.
Explanation of Solution
Cobalt is present in lower oxidation state such as + 2 and thus formula of given compound is CoCl2.
(c)
Interpretation:
Interpret formula of Silver sulfide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR
The formula of given compound is AgF.
Explanation of Solution
Ag is present in lower oxidation state such as + 1 and thus formula of given compound is AgF.
(d)
Interpretation:
Interpret formula of Mercurous bromide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR
The formula of given compound is HgBr2.
Explanation of Solution
Hg is present in lower oxidation state such as + 2 and thus formula of given compound is HgBr2.
(e)
Interpretation:
Interpret formula of Mercuric oxide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR
The formula of given compound is Hg2 O3.
Explanation of Solution
Hg is present in higher oxidation state such as + 3 and thus formula of given compound is Hg2 O3.
(f)
Interpretation:
Interpret formula of Chromium (iii) sulfide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR
The formula of given compound is Cr2 S3.
Explanation of Solution
Cr is present in higher oxidation state such as + 3 and thus formula of given compound is Cr2 S3.
(g)
Interpretation:
Interpret formula of Plumbic oxide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR
The formula of given compound is PbO2.
Explanation of Solution
Pb is present in higher oxidation state such as + 4 and thus formula of given compound is PbO2.
(h)
Interpretation:
Interpret formula of Potassium nitride.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR
The formula of given compound is K3 N.
Explanation of Solution
N is present in oxidation state such as -3 and thus formula of given compound is K3 N.
(i)
Interpretation:
Interpret formula of Stannous fluoride.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR
The formula of given compound is SnF2.
Explanation of Solution
Sn2 + is present in lower oxidation state such as + 2 and thus formula of given compound is SnF2.
(j)
Interpretation:
Interpret formula of Ferric oxide.
Concept Introduction:
Binary ionic compound is the species contains two ions in the compound to form a chemical species.
The formula of Binary ion contains the formula of cation first then proceeded the formula of anion. The formula of cation in Binary ion remain same to that of metal while for anion its formula ends by suffix ‘ate’ while anion of group 6 and 7 ends with suffix ‘ide’.
For cation with lower oxidation state formula is ended with ‘ous’ and with high oxidation state is ended with ‘ic’.

Answer to Problem 26CR
The formula of given compound is Fe2 O3.
Explanation of Solution
Fe is present in higher oxidation state such as + 3 and thus formula of given compound is Fe2 O3.
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Chapter 5 Solutions
Introductory Chemistry: A Foundation
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- Provide the missing information for each of the four reactions: *see imagearrow_forward6. Chlorine dioxide (CIO) is used as a disinfectant in municipal water-treatment plants. It decomposes in a first-order reaction with a rate constant of 14 s. How long would it take for an initial concentration of 0.06 M to decrease to 0.02 M? [6 pts]arrow_forwardIf possible, replace an H atom on the a carbon of the molecule in the drawing area with a methyl group substituent, and replace an H atom on the ẞ carbon with a hydroxyl group substituent. If one of the substituents can't be added for any reason, just don't add it. If neither substituent can be added, check the box under the drawing area. en HO OHarrow_forward
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- help with the rf values i am so confusedarrow_forwardPredict the organic reactant of X and Y that are involved in the reaction below, and draw the skeletal ("line") structures of the missing organic reactant. Please include all steps & drawings & explanations.arrow_forwardPredict the major organic product for this reaction.arrow_forward
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