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(a)
Interpretation:
To determine the number of proton and electron of the ionic species Mg2+.
Concept Introduction:
Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.
Answer to Problem 24CR
The number of proton and electron of Mg2 + species is 12 and 10 respectively.
Explanation of Solution
(b)
Interpretation:
To determine the number of proton and electron of the ionic species Fe2+.
Concept Introduction:
Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.
Answer to Problem 24CR
The number of proton and electron of Fe2 + species is 26 and 24 respectively.
Explanation of Solution
Atomic number of an ionic species represents the number of proton so, number of proton of Fe2 + is 26 and the number of electron of cationic species is the difference of number of proton and charge given. Number of electron = 26-2 = 24.
(c)
Interpretation:
To determine the number of proton and electron of the ionic species Fe3+.
Concept Introduction:
Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.
Answer to Problem 24CR
The number of proton and electron of Fe3 + species is 26 and 23 respectively.
Explanation of Solution
Atomic number of an ionic species represents the number of proton so, number of proton of Fe2 + is 26 and the number of electron of cationic species is the difference of number of proton and charge given. Number of electron = 26-3 = 23.
(d)
Interpretation:
To determine the number of proton and electron of the ionic species F-.
Concept Introduction:
Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.
Answer to Problem 24CR
The number of proton and electron of F- species is 9 and 10 respectively.
Explanation of Solution
Atomic number of an ionic species represents the number of proton so, number of proton of Mg2 + is 9 and the number of electron of cationic species is the addition of number of proton and charge given. Number of electron = 9+1 = 10.
(e)
Interpretation:
To determine the number of proton and electron of the ionic species Ni2+.
Concept Introduction:
Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.
Answer to Problem 24CR
The number of proton and electron of Ni2 + species is 28 and 26 respectively.
Explanation of Solution
Atomic number of an ionic species represents the number of proton so, number of proton of Ni2 + is 28 and the number of electron of cationic species is the difference of number of proton and charge given. Number of electron = 28-2 = 26.
(f)
Interpretation:
To determine the number of proton and electron of the ionic species Zn2+.
Concept Introduction:
Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.
Answer to Problem 24CR
The number of proton and electron of Zn2 + species is 30 and 28 respectively.
Explanation of Solution
Atomic number of an ionic species represents the number of proton so, number of proton of Zn2 + is 30 and the number of electron of cationic species is the difference of number of proton and charge given. Number of electron = 30-2 = 28.
(g)
Interpretation:
To determine the number of proton and electron of the ionic species Co3+.
Concept Introduction:
Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.
Answer to Problem 24CR
The number of proton and electron of Co3 + species is 27 and 24 respectively.
Explanation of Solution
Atomic number of an ionic species represents the number of proton so, number of proton of Co3 + is 27 and the number of electron of cationic species is the difference of number of proton and charge given. Number of electron = 27-3 = 24.
(h)
Interpretation:
To determine the number of proton and electron of the ionic species N3-.
Concept Introduction:
Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.
Answer to Problem 24CR
The number of proton and electron of N3 - species is 7 and 10 respectively.
Explanation of Solution
Atomic number of an ionic species represents the number of proton so, number of proton of N3 - is 7 and the number of electron of cationic species is the addition of number of proton and charge given. Number of electron = 7+3 = 10.
(i)
Interpretation:
To determine the number of proton and electron of the ionic species S2-.
Concept Introduction:
Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.
Answer to Problem 24CR
The number of proton and electron of S2 - species is 16 and 18 respectively.
Explanation of Solution
Atomic number of an ionic species represents the number of proton so, number of proton of S2 - is 16 and the number of electron of cationic species is the addition of number of proton and charge given. Number of electron = 16+2 = 18.
(j)
Interpretation:
To determine the number of proton and electron of the ionic species Rb+.
Concept Introduction:
Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.
Answer to Problem 24CR
The number of proton and electron of Rb+ species is 37and 36 respectively.
Explanation of Solution
Atomic number of an ionic species represents the number of proton so, number of proton of Rb+ is 37 and the number of electron of cationic species is the difference of number of proton and charge given. Number of electron = 37-1=36.
(k)
Interpretation:
To determine the number of proton and electron of the ionic species Se2-.
Concept Introduction:
Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.
Answer to Problem 24CR
The number of proton and electron of Se2 - species is 34 and 36 respectively.
Explanation of Solution
Atomic number of an ionic species represents the number of proton so, number of proton of Se2 - is 34 and the number of electron of cationic species is the addition of number of proton and charge given. Number of electron = 34+2 = 36.
(l)
Interpretation:
To determine the number of proton and electron of the ionic species K+.
Concept Introduction:
Ions are formed by loss or gain of an electron. If an atom gain the electron it will carry positive charge and if it lose the electron it will carry the positive charge. The electron present in the outermost shell of an atom is mostly responsible for formation of ions. If the number of proton is less than number of electron the species is anionic and if the number of proton is higher than number of electron the species if cationic.
Answer to Problem 24CR
The number of proton and electron of K+ species is 19 and 18 respectively.
Explanation of Solution
Atomic number of an ionic species represents the number of proton so, number of proton of K+ is 19 and the number of electron of cationic species is the difference of number of proton and charge given. Number of electron = 19-1 = 18.
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Chapter 5 Solutions
Introductory Chemistry: A Foundation
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