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Three forces
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Physics for Scientists and Engineers: Foundations and Connections
- A cart of mass 8.00 kg was moved by applying two constant forces. Force 1 is 28.0 N at 42.0°, and Force 2 is 13.0 N at 110°. Initially, the cart has a velocity of (3.50 i +2.20 j) m/s. a. Express the two forces in in unit-vector notation. Ans. F = (20.81 i + 18.74 j)N, F, = (-4.45 i + 12.22 j)N b. Find the total force exerted on the cart. Ans. EF = (16.36 i+ 30.96 j)N or 35.02 N c. Find the angle at which the total force is applied. Ans. 62.15°arrow_forwardA particle of mass 5.70 kg moves in the horizontal xy plane. The only force acting on the particle with component in the xy plane has expression (in newtons) F =4.70x2ı^, where x is in meters. Assume that the particle's trajectory is a straight line from the position (in meters) r0=2.10ı^ +2.10ȷ^ to the position (in meters) rf=6.50ı^ +2.10ȷ^. Also consider that its speed at position r0 has a magnitude of 3.80 m/s. Calculate the magnitude (in m/s) of the particle's velocity at position rf. Give your answer to three significant figures. (only numbers)arrow_forwardA runner of mass 62.0 kg initially moves at a speed of 8.05 m/s.How long must an average external force of 1.60* 10^2 N act to bring the runner to rest?arrow_forward
- Chapter 05, Problem 010 GO A 0.180 kg particle moves along an x axis according to x(t) = - 14.0 + 2.00 t + 4.00 2- 5.00 t, with x in meters and t in seconds. In unit-vector notation, what is the net force acting on the particle at t = 3.30 s ? Give an expression for the (a) x, (b) y and (c) z components. (a) Number Units (b) Number Units (c) Number Units Click if you would like to Show Work for this question: Open Show Work Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER powered by MapleNet ere to search 1:51 PM ENG 4/4/2021 ASUS 19home prt sc pause break delete f10 end f1Pgup f12Pgdn insert & 21 4. 8 backspo-arrow_forwardA drone is being directed across a frictionless ice covered lake. The mass of the drone is 1.50 kg, and its velocity is 3.00i ^ m/s . After 10.0 s, the velocity is 9.00i ^ + 4.00j ^ m/s . If a constant force in the horizontal direction is causing this change in motion, find (a) the components of the force and (b) the magnitude of the force.arrow_forward1. A cart of mass 8.00 kg was moved by applying two constant forces. Force 1 is 28.0 N at 42.0°, and Force 2 is 13.0 N at 110°. Initially, the cart has a velocity of (3.50 i +2.20 m/s. a. Express the two forces in in unit-vector notation. Ans. F = (20.81 i+ 18.74 j)N, F, = (-4.45 i + 12.22 j)N b. Find the total force exerted on the cart. Ans. E F = (16.36 i + 30.96 j)N or 35.02 N c. Find the angle at which the total force is applied. Ans. 62.15° EERINarrow_forward
- Two forces F, = (55.76î - 12.93ĵ) N and F, = (27.41î – 72.94ĵ) N are exerted on a particle. The particle's mass is 10.14 kg. %3D (a) Find the particle's acceleration in component form. (Express your answer in vector form.) a = m/s? (b) What are the magnitude and direction of the acceleration? magnitude m/s2 direction ° counterclockwise from the +x axisarrow_forwardA desperate hiker has to think fast to help his friend who has fallen below him. Quickly, he ties m, a rope to a rock of mass m, = 3.90 x 10? kg and makes his way over the ledge (see the figure). If the coefficient of static friction between the rock and the ground is µs = 0.283, and the mass of the hiker is m, = 70.1 kg, what is the maximum mass of the friend m; that the rock can hold so the hikers can then make their way up over the ledge? Assume the rope is parallel to the ground and the point where the rope passes over the ledge is frictionless. kg IIarrow_forwardAn electron is a subatomic particle (m = 9.11 x 1031 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +5.72 x 105 m/s to a final velocity of 2.64 x 106 m/s while traveling a distance of 0.0783 m. The electron's acceleration is due to two electric forces parallel to the x axis: F1 = 9.44 x 10-17 N, and F2, which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force F2. F F FF Voarrow_forward
- Two constant forces act on an object of mass m = 4.30 kg object moving in the xy plane as shown in the figure below. Force F, is 26.5 N at 35.0°, and force F, is 48.0 N at 150°. At time t = 0, the object is at the origin and has velocity (3.50î + 2.15j) m/s. 150° 35.0° (a) Express the two forces in unit-vector notation. F, - N (b) Find the total force exerted on the object. N (c) Find the object's acceleration. m/s2 Now, consider the instant t = 3.00 s. (d) Find the object's velocity. m/s (e) Find its position. (f) Find its kinetic energy from V½mv2. kJ (g) Find its kinetic energy from 2mv,2 + EF · AF. kJarrow_forwardA mug of root beer is sliding across a horizontal table with a constant velocity of 5.0[m/s], and is experiencing a friction force. If the mug has a total mass of 2.60[kg] and μk = 0.250, find the force due to friction. Express your answer in N.arrow_forwardA sailboat with a mass of 2 x 103 kg experiences a tidal force of 3 x 103 N directed to the east and a wind force against its sails with a magnitude of 6 x 103 N directed toward the northwest (45°N of W). What is the magnitude of the resultant acceleration of the boat? O 9.68 m/s^2 O 2.21 m/s^2 O 5.14 m/s^2 8.92 m/s^2arrow_forward
- Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning