Consider the following balanced chemical equation: A + 5B → 3C + 4D a. Equal masses of A and B are reacted. Complete each of the following with either “A is the limiting reactant because “; “B is the limiting reactant because ____ “; or “we cannot determine the limiting reactant because _____ i. If the molar mass of A is greater than the molar mass of B, then ii. If the molar mass of B is greater than the molar mass of A, then b. The products of the reaction are carbon dioxide (C) and water (D). Compound A has a similar molar mass to carbon dioxide. Compound B is a diatomic molecule. Identify compound B, and support your answer. c. Compound A is a hydrocarbon that is 81.7 1% carbon by mass. Determine its empirical and molecular formulas.
Consider the following balanced chemical equation: A + 5B → 3C + 4D a. Equal masses of A and B are reacted. Complete each of the following with either “A is the limiting reactant because “; “B is the limiting reactant because ____ “; or “we cannot determine the limiting reactant because _____ i. If the molar mass of A is greater than the molar mass of B, then ii. If the molar mass of B is greater than the molar mass of A, then b. The products of the reaction are carbon dioxide (C) and water (D). Compound A has a similar molar mass to carbon dioxide. Compound B is a diatomic molecule. Identify compound B, and support your answer. c. Compound A is a hydrocarbon that is 81.7 1% carbon by mass. Determine its empirical and molecular formulas.
Solution Summary: The author explains that the compound B is identified, the empirical and molecular formula of compound A is calculated.
Consider the following balanced chemical equation:
A
+
5B
→
3C
+
4D
a. Equal masses of A and B are reacted. Complete each of the following with either “A is the limiting reactant because “; “B is the limiting reactant because ____ “; or “we cannot determine the limiting reactant because _____
i. If the molar mass of A is greater than the molar mass of B, then
ii. If the molar mass of B is greater than the molar mass of A, then
b. The products of the reaction are carbon dioxide (C) and water (D). Compound A has a similar molar mass to carbon dioxide. Compound B is a diatomic molecule. Identify compound B, and support your answer.
c. Compound A is a hydrocarbon that is 81.7 1% carbon by mass. Determine its empirical and molecular formulas.
1) Draw the structures of D-lysine and L-lysine and assign R/S configuration
(showing your workings).
2) Draw the predominant ionisation forms of the free amino acid lysine, at pH 1.0,
8.0, and 11.0. pKa values: 2.2 (-COOH), 9.0 (α-NH3+), 10.5 (side-chain).
3) Calculate (showing your workings) the % of the different ionized species that
are present in a 1.00 M solution of L-proline at pH = 10.0. pKa values: 1.95 (-
COOH), 10.64 (α-NH3*).
4)
a) Draw the tripeptide Tyr-Pro-Lys once with a trans peptide bond between Tyr
and Pro and once with a cis peptide bond between Tyr and Pro.
b) The electrospray ionization mass spectrum (ESI-MS) of the tripeptide you
designed in part (a) shows peaks indicative of mono-protonation and di-
protonation of the tripeptide. At what values of m/z would these peaks be
expected (no fragmentation)? Briefly explain your answer (showing your
workings).
5) How could the sequence of Ala-Met-Thr be distinguished from that of Thr-Ala-
Met by tandem ESI-MS-MS?…
LABORATORY REPORT FORM
Part I. Determination of the Formula of a Known Hydrate
1. Mass of empty evaporating dish
3. Mass of hydrate
Using subtraction
or mass by difference,
find the mass of
the hydrate
76.96
-75.40
75.40g
76.968
1.568
01.56
76.90 g
2. Mass of evaporating dish + hydrate
4. Mass of evaporating dish + hydrate (after heating)
First 76.98 g
Third 76.66g
Second
Fourth (if necessary) 76.60g
5. Mass of anhydrate
6. Mass of water lost by the hydrate
7. Percent of water of hydration
(Show Calculations)
8. Moles of water
(Show Calculations)
mol
mass of water
=
MM of water (g/m)
9. Moles of anhydrate
(Show Calculations)
10. Ratio of moles of water to moles of anhydrate
11 F(Show Calculations)
11. Formula of hydrate
- Mass of water (g) x 100
% water hydration
g
g
%
Mass of hydrate (9) x IC
% = (Mass of hydrate- mass of an)
mass of hydrate (g)
% = (1.569-
× 100=
mol
1.569
mol Mol Mass of
anhydrate/MM
of anhydrate
12. What was the color of the hydrate?
blue
What was the color of the…
compared t-critical with t-calculated and 95% confidence interval to answer this question
Chapter 5 Solutions
Bundle: Chemistry: An Atoms First Approach, Loose-leaf Version, 2nd + OWLv2 with Student Solutions Manual, 4 terms (24 months) Printed Access Card
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell