Explanation Let sin θ = L 2 R .then L = 2 R sin θ h = R − R cos θ = R ( 1 − cos θ ) = 1 2 L sin To determine b) To find out the maximum vertical displacement for L + m = 2 R θ and conclude that sin θ θ = L L + m .

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Question

Chapter 4.7, Problem 32E

To determine

a)

To find out the maximum vertical displacement for L=2R sin θ and conclude that h=L(1−cos θ)2 sin θ.

To determine

b)

To find out the maximum vertical displacement for L+m=2R θ and conclude that sinθθ=LL+m.

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Chapter 4.7, Problem 31E

Chapter 4.7, Problem 33E

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Chapter 4 Solutions

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a) To find out the maximum vertical displacement for L = 2 R sin θ and conclude that h = L ( 1 − cos θ ) 2 sin θ .

Solution Summary: The author explains the solution obtained as L(1-mathrmcos

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a)

To find out the maximum vertical displacement for L=2R sin θ and conclude that h=L(1−cos θ)2 sin θ.

b)

To find out the maximum vertical displacement for L+m=2R θ and conclude that sinθθ=LL+m.

Want to see the full answer?

Chapter 4 Solutions

a) To find out the maximum vertical displacement for L = 2 R sin θ and conclude that h = L ( 1 − cos θ ) 2 sin θ .

Solution Summary: The author explains the solution obtained as L(1-mathrmcos

Videos

a) To find out the maximum vertical displacement for L=2R sin θ and conclude that h=L(1−cos θ)2 sin θ.

b) To find out the maximum vertical displacement for L+m=2R θ and conclude that sinθθ=LL+m.

Want to see the full answer?

Chapter 4 Solutions

a)

To find out the maximum vertical displacement for L=2R sin θ and conclude that h=L(1−cos θ)2 sin θ.

b)

To find out the maximum vertical displacement for L+m=2R θ and conclude that sinθθ=LL+m.