Explanation Given: y = | 3 x − 9 | We know that the critical points are the points at which the derivatives of the function become zero or undefined. Let, f ( x ) = y = | 3 x − 9 | = 3 | x − 3 | Instead of differentiating we solve the above function. For x < 3, we have f’(x) = – 3 and for x > 3, we have f’(x) = 3. Now, as x → 3 − , we have f ( x ) − f ( 3 ) x − 3 = 3 ( 3 − x ) − 0 x − 3 → − 3 Whereas, x → 3 + , we have f ( x ) − f ( 3

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Chapter 4.2, Problem 54E

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To find all the critical points of the function y=|3x−9|

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Chapter 4.2, Problem 53E

Chapter 4.2, Problem 55E

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Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

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To find all the critical points of the function y = | 3 x − 9 |

Solution Summary: The author explains that the critical points are the points at which the derivatives of the function become zero or undefined.

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To find all the critical points of the function y=|3x−9|

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Chapter 4 Solutions